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JulsSmile [24]
3 years ago
10

Evaluate the expression 1/5^−3⋅1/5^6

Mathematics
2 answers:
garik1379 [7]3 years ago
6 0

Answer:

The answer is 1 953 125

Step-by-step explanation:

(1/5)^(-3)/(1/5)^6

First, we evaluate the resultant power: (1/5)^(-3)/(1/5)^6=(1/5)^(-3-6)=(1/5)^(-9)

Then, we evaluate the value of the expression: (1/5)^(-9)=5^9=1 953 125

Thus, the answer is 1 953 125

uranmaximum [27]3 years ago
5 0

Answer: Hey Jasmine :)

The answer is down below in the image

Step-by-step explanation:

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Which of the following sequences are not geometric? (check all that apply) a. 2,10,50,250,1250 b. 1,4,9,16,25,36 c. -4,-2,-1,-0.
Romashka [77]
A is geometric because each number is multiplied by 5.

B is not geometric because it is an arithmetic sequence. 

C is a geometric sequence because each number is divided by 2.

D is neither geometric not arithmetic because there is no common ratio and there is not a pattern being added or subtracted to each number.

So, your answer should be B and D.
8 0
3 years ago
A pancake recipe requires two and three quarters cups of milk to one cup of flour. If three and two thirds cups of milk is used,
MrRissso [65]

Answer:

3/4 cups of flour are needed.

Step-by-step explanation:

(3 2/3)/1=(2 3/4)/x

(11/3)/1=(11/4)/x cross multiply.

11x/3=11/4 cross multiply.

4*11x=3*11

44x=33

x=33/44

x=3/4

3 0
2 years ago
If a cube has a<br> volume of 8 cm<br> what is it's side<br> length?
lana [24]
Side length: 2 cm.

Volume of a cube:
V=a^3
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If v=8, the formula would now be 8=a^3

Take the cube root of both sides

a=2.
5 0
4 years ago
Which of the following inequalities is not true?
Galina-37 [17]
The answer is C or the third answer choice because the absolute value of nine is equivalent to the absolute value of nine. The meaning of absolute value is the number of places away from zero on the number line, and both 9 and -9 are equal distance from zero.
6 0
3 years ago
Read 2 more answers
(cotx+cscx)/(sinx+tanx)
Butoxors [25]

Answer:   \bold{\dfrac{cot(x)}{sin(x)}}

<u>Step-by-step explanation:</u>

Convert everything to "sin" and "cos" and then cancel out the common factors.

\dfrac{cot(x)+csc(x)}{sin(x)+tan(x)}\\\\\\\bigg(\dfrac{cos(x)}{sin(x)}+\dfrac{1}{sin(x)}\bigg)\div\bigg(\dfrac{sin(x)}{1}+\dfrac{sin(x)}{cos(x)}\bigg)\\\\\\\bigg(\dfrac{cos(x)}{sin(x)}+\dfrac{1}{sin(x)}\bigg)\div\bigg[\dfrac{sin(x)}{1}\bigg(\dfrac{cos(x)}{cos(x)}\bigg)+\dfrac{sin(x)}{cos(x)}\bigg]\\\\\\\bigg(\dfrac{cos(x)}{sin(x)}+\dfrac{1}{sin(x)}\bigg)\div\bigg(\dfrac{sin(x)cos(x)}{cos(x)}+\dfrac{sin(x)}{cos(x)}\bigg)

\text{Simplify:}\\\\\bigg(\dfrac{cos(x)+1}{sin(x)}\bigg)\div\bigg(\dfrac{sin(x)cos(x)+sin(x)}{cos(x)}\bigg)\\\\\\\text{Multiply by the reciprocal (fraction rules)}:\\\\\bigg(\dfrac{cos(x)+1}{sin(x)}\bigg)\times\bigg(\dfrac{cos(x)}{sin(x)cos(x)+sin(x)}\bigg)\\\\\\\text{Factor out the common term on the right side denominator}:\\\\\bigg(\dfrac{cos(x)+1}{sin(x)}\bigg)\times\bigg(\dfrac{cos(x)}{sin(x)(cos(x)+1)}\bigg)

\text{Cross out the common factor of (cos(x) + 1) from the top and bottom}:\\\\\bigg(\dfrac{1}{sin(x)}\bigg)\times\bigg(\dfrac{cos(x)}{sin(x)}\bigg)\\\\\\\bigg(\dfrac{1}{sin(x)}\bigg)\times cot(x)}\qquad \rightarrow \qquad \dfrac{cot(x)}{sin(x)}

6 0
3 years ago
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