What is 5,382,619 rounded to the nearest 1,000

Write the following number in standard decimal form four tenths

Crazy boy [7]

0.4 is four tenths. 0.4 = 4/10=2/5

8 0

3 years ago

Three ballet dancers are positioned on stage. Greta is straight behind Bryan and directly left of Alice. If Bryan and Greta are

Neko [114]

Answer:

12

Step-by-step explanation:

4 0

2 years ago

A policyholder has probability 0.7 of having no claims, 0.2 of having exactly one claim, and 0.1 of having exactly two claims. C

Sladkaya [172]

Answer:

0.89.

Step-by-step explanation:

So, we are given the following data or parameters or information which is going to aid in the solution to this question or problem. So, the data or parameters are;

(1). "probability 0.7 of having no claims, 0.2 of having exactly one claim, and 0.1 of having exactly two claims."

(2). " distributed on the interval [0,60] and are independent."

(3). "The insurer covers 100% of each claim."

So, taking (1) above we will have;

(Total probability= 0.7 + 0.2 + 0.1 = 0.1)

A = { (0.7 × 0)^2 + (0.2 × 1)^2 + ( 0.1 × 2)^2 =( 0.4) +( 0.4) = 0.8.

0.8 + total probability = 0.8 + 0.1 = 0.9.

So, from the question, we are to "Calculate the probability that the total beneﬁt paid to the policyholder is 48 or less."

Hence, P< 48/A = P < 48/0.9 = P < 53.33.

Thus, 53.33/60 = 0.89.

6 0

3 years ago

C = ?<br>Be sure to evaluate the square root

Butoxors [25]

Hope this will help u .

If my ans was helpful, u can follow me.

4 0

3 years ago

A Pew Internet poll asked cell phone owners about how they used their cell phones. One question asked whether or not during the

EastWind [94]

Answer:

a) $\hat p=\frac{471}{1024}=0.460$

The standard error is given by:

$SE= \sqrt{\frac{\hat p(1-\hat p)}{n}}=\sqrt{\frac{0.460(1-0.460)}{1024}}=0.0156$

And the margin of error is given by:

$ME=z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}=1.96\sqrt{\frac{0.460(1-0.460)}{1024}}=0.0305$

b) The 99% confidence interval would be given by (0.429;0.491)

Step-by-step explanation:

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

Data given and notation

n=1024 represent the random sample taken

X=471 represent the people responded that they had used their cell phone while in a store within the last 30 days to call a friend or family member for advice about a purchase they were considering

$\hat p=\frac{471}{1024}=0.460$ estimated proportion of people responded that they had used their cell phone while in a store within the last 30 days to call a friend or family member for advice about a purchase they were considering

p= population proportion of people responded that they had used their cell phone while in a store within the last 30 days to call a friend or family member for advice about a purchase they were considering

Part a

The confidence interval would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 95% confidence interval the value of $\alpha=1-0.95=0.05$ and $\alpha/2=0.025$ , with that value we can find the quantile required for the interval in the normal standard distribution.