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3 years ago

Will mark BRAINLIEST!! — Point H is the circumcenter of triangle DEF. Which must be true? Check ALL that apply. See image.

Mathematics

1 answer:

Margarita [4]3 years ago

8 0

Answer:

A, C, F

Step-by-step explanation:

Definition: The circumcenter is the center of the triangle's circumcircle - the circle that passes through all three of the triangle's vertices. If point H is the circumcenter of the triangle DEF, then the circumcircle passes through its vertices D, E and F (option A is true).

Option B is false, the circumcircle doesn't pass through the points L, M and N. This option is true for inscribed circle, not for circumcircle.

Option C is true, because HD and HE are the radii of the circumcircle.

Option D is false. This option is true for inscribed circle, not for circumcircle.

Option E is false. This option is true for inscribed circle, not for circumcircle.

Option F is true, because both these angles are right angles.

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We are standing on the top of a 1680 ft tall building and throw a small object upwards. At every second, we measure the distance

MAVERICK [17]

Answer:

a) The height of the small object 3 seconds after being launched is 2304 feet.

b) The small object ascends 128 feet between 5 seconds and 7 seconds.

c) The object will take 6 and 10 seconds after launch to reach a height of 2640 feet.

d) The object will take 21 seconds to hit the ground.

Step-by-step explanation:

The correct formula for the height of the small object is:

$h(t) = -16\cdot t^{2}+256\cdot t+1680$ (1)

Where:

$h$ - Height above the ground, measured in feet.

$t$ - Time, measured in seconds.

a) The height of the small object at given time is found by evaluating the function:

$h(3\,s)= -16\cdot (3\,s)^{2}+256\cdot (3\,s)+1680$

$h(3\,s) = 2304\,ft$

The height of the small object 3 seconds after being launched is 2304 feet.

b) First, we evaluate the function at $t = 5\,s$ and $t = 7\,s$ :

$h(5\,s)= -16\cdot (5\,s)^{2}+256\cdot (5\,s)+1680$

$h(5\,s) = 2560\,s$

$h(7\,s)= -16\cdot (7\,s)^{2}+256\cdot (7\,s)+1680$

$h(7\,s) = 2688\,s$

We notice that the small object ascends in the given interval.

$\Delta h = h(7\,s)-h(5\,s)$

$\Delta h = 128\,ft$

The small object ascends 128 feet between 5 seconds and 7 seconds.

c) If we know that $h = 2640\,ft$ , then (1) is reduced into this second-order polynomial:

$-16\cdot t^{2}+256\cdot t-960=0$ (2)

All roots of the resulting equation come from the Quadratic Formula:

$t_{1} = 10\,s$ and $t_{2}= 6\,s$

The object will take 6 and 10 seconds after launch to reach a height of 2640 feet.

d) If we know that $h = 0\,ft$ , then (1) is reduced into this second-order polynomial:

$-16\cdot t^{2}+256\cdot t +1680 = 0$ (3)

All roots of the resulting equation come from the Quadratic Formula:

$t_{1} = 21\,s$ and $t_{2} = -5\,s$

Just the first root offers a solution that is physically reasonable.

The object will take 21 seconds to hit the ground.

8 0

3 years ago

please help with maths work

prisoha [69]

Given:

In a right angle triangle ABC, $\angle B=90^\circ,x=8.7\ m$ , and $\theta = 45^\circ$

To find:

The value of AC.

Solution:

In a right angle triangle,

$\cos \theta =\dfrac{Adjacent}{Hypotenuse}$

$\cos \theta =\dfrac{BC}{AC}$

$\cos (45^\circ) =\dfrac{8.7}{AC}$

$\dfrac{1}{\sqrt{2}}=\dfrac{8.7}{AC}$

On cross multiplication, we get

$AC=8.7\times \sqrt{2}$

$AC=12.30365799$

$AC\approx 12.304$

Therefore, the measure of AC is 12.304 m.

3 0

3 years ago

Ment in

ASHA 777 [7]

Answer:

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decision.

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Fledge to

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I summarized the court's argment in

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answer? Check all of the boxes that apply.

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I identified the premises and conclusion.

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decision.

I evaluated the arguments supporting the

decision.

I included background knowledge.

I recognized that the Constitution takes on

different meanings as societal values

changeument.

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decision.

I evaluated the arguments supporting the

decision.

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I recognized that the Constitution takes on

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Step-by-step explanation:

6 0

2 years ago

I really need help!!!!

Akimi4 [234]

I think 2 is f
and 3 is c

8 0

4 years ago

Read 2 more answers

In a curvilinear relationship, increases in the values of one variable are accompanied by systematic increases and decreases in

maksim [4K]

Answer:

Nonmonotonic

Step-by-step explanation:

A non-monotonic function is a function that is increasing and decreasing on different intervals of its domain. As we can see that same thing happens in a curvilinear relationship, that is why it is aslo called a Non-monotonic.

5 0

3 years ago