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vodomira [7]
3 years ago
5

When a number is increased by 21%, the result is 102. What is the original number to the nearest tenth?

Mathematics
1 answer:
ANEK [815]3 years ago
7 0

Answer:

84.30

Step-by-step explanation:

Let the number = x

x + 21/100 x = 102             Combine the left hand side.

x + 0.21x = 102                  Add the left

x(1 + 0.21) = 102                 Combine

1.21x = 102                         Divide by 1.21

1.21x/1.21=102/1.21

x = 84.2795     To the nearest 1/10

x = 84.30

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A suitable calculator can find the value of this ratio for you.

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In the given equation, as the value of <em>y</em> increase, the value of <em>x</em> also

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