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2 years ago

PLEASE ANSWER:

Mathematics

1 answer:

Lerok [7]2 years ago

4 0

Answer:

5r + 2p + 6

Step-by-step explanation:

4r+r = 5r

9-3 = 6

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Mitchell buys a rug that is 3.8 meters long and 0.9 meters wide. How many square meters does the rug cover? Record your answer b

Bond [772]

Answer:3.42

Step-by-step explanation:to get the answer to a area equation you need to multiply the length by the width.

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3 years ago

Choose the equation of the line that is parallel to the x-axis.

True [87]

Answer:

y = 4

Step-by-step explanation:

y = 4

The line will always go along y = 4 and therefore is parallel to the x axis

7 0

3 years ago

Read 2 more answers

Wendy needs to purchase 44 vases, which cost $3 each, and flowers for the vases, which cost $2 each. She has $308 to spend on he

kirill [66]

Answer: a

Step-by-step explanation:

44 times 3 =$132 for vases

x it is flowers, the price of one flower is $2

2x +132 must be less or equal 308

4 0

3 years ago

Read 2 more answers

Geometry!!!!!!!!!!!!!!!!!!!!!!!!

Stella [2.4K]

Given:

Given that O is the center of the circle.

The radius of the circle is 3 m.

The measure of ∠AOB is 30°

We need to determine the length of the major arc ACB

Measure of major ∠AOB:

The measure of major angle AOB can be determined by subtracting 360° and 30°

Thus, we have;

$Major \ \angle AOB=360-30$

$Major \ \angle AOB=330^{\circ}$

Thus, the measure of major angle is 330°

Length of the major arc ACB:

The length of the major arc ACB can be determined using the formula,

$m \widehat{ACB}=(\frac{\theta}{360})2 \pi r$

Substituting r = 3 and $\theta=330$ , we get;

$m \widehat{ACB}=(\frac{330}{360})2 \pi (3)$

$m \widehat{ACB}=\frac{1980}{360}\pi$

$m \widehat{ACB}=5.5 \pi$

Thus, the length of the major arc ACB is 5.5π m

8 0

3 years ago

RSB [31]

Answer:

Step-by-step explanation:

3x² - 3x + 7 = 0

a = 3 ; b = -3 and c = 7

D = b² - 4ac = (-3)² - 4*3*7

D = 9 - 84 = - 75

D = 75i²

√D = √75i² = $\sqrt{5*5*3 * i * i}= 5i\sqrt{3}$

$x = \dfrac{-b+\sqrt{D}}{2a} \ ; \ x=\dfrac{-b-\sqrt{D}}{2a}\\\\ \\x=\dfrac{3+5i\sqrt{3}}{6} ; \ ; x = \dfrac{3-5i\sqrt{3}}{6}\\\\\\x =\dfrac{3}{6}+\dfrac{5i\sqrt{3}}{6} ; \ ; x=\dfrac{3}{6}-\dfrac{5i\sqrt{3}}{6}\\\\\\Solution:\\\\x=\dfrac{1}{2}+\dfrac{5\sqrt{3}}{6}i ; \ ; x=\dfrac{1}{2}-\dfrac{5\sqrt{3}}{6}i$

5 0

2 years ago