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3 years ago

Round .0091 to the thousandths

2 answers:

6 0

The thousandths place is always the third place after the decimal. Since the nine is there, the one tells it what to do. One is small so it stays at nine. A jingle is 5 and above move up one and 4 and below stay the same. The answer is 0.009

malfutka [58]3 years ago

3 0

Answer:

0.009

Step-by-step explanation:

We have been given a decimal number 0.0091. We are asked to round our given number of nearest thousandth.

Rounding to nearest thousandth means to round to three places after decimal.

We can see that fourth digit after decimal is less than 5, so we will round 3rd digit after decimal to 9.

$0.0091\approx 0.009$

Therefore, our given number rounded to the thousandths would be 0.009.

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3 years ago

You have 32 Tbsp of peppercorns. You need 0.25 teaspoons to make one serving of Cajun seasoning. How many servings can you make?

jonny [76]

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3 0

3 years ago

Read 2 more answers

1. There are 78 sophomores at a school. Each is required to take at least one year of either chemistry or physics, but they may

SVETLANKA909090 [29]

We are given that there are a total of 78 students. If we set the following variables:

$\begin{gathered} C=\text{students only in chemestry} \\ P=\text{students only in physics} \\ PC=\text{students in physics and chemistry} \end{gathered}$

Then, the sum of all of these must be 78, that is:

$C+P+PC=78$

Since there are 15 in chemistry and physics and 47 in chemistry, we may replace that into the equation and we get:

$47+P+15=78$

Simplifying:

$62+P=78$

Now we solve for P by subtracting 62 on both sides:

$\begin{gathered} 62-62+P=78-62 \\ P=16 \end{gathered}$

Therefore, there are 16 students in physics

3 0

1 year ago

alisha [4.7K]

Answer:

$d=3\sqrt{2}\ units$

Step-by-step explanation:

The complete question is

Line L contains points (3, 5) and (7, 9). Points P has coordinates (2, 10). Find the distance from P to L

step 1

Find the equation of the line L contains points (3,5) and (7,9)

Find the slope

The formula to calculate the slope between two points is equal to

$m=\frac{y2-y1}{x2-x1}$

substitute the given values

$m=\frac{9-5}{7-3}$

$m=\frac{4}{4}=1$

Find the equation of the line in point slope form

$y-y1=m(x-x1)$

we have

$m=1\\point\ (3,5)$

substitute

$y-5=(1)(x-3)$

isolate the variable y

$y=x-3+5$

$y=x+2$ -----> equation A

step 2

Find the equation of the perpendicular line to the given line L that passes through the point P

Remember that

If two lines are perpendicular, then their slopes are opposite reciprocal

The slope of the given line L is $m=1$

The slope of the line perpendicular to the given line L is

$m=-1$

Find the equation of the line in point slope form

$y-y1=m(x-x1)$

we have

$m=-1\\point\ (2,10)$

substitute

$y-10=-(x-2)$

isolate the variable y

$y=-x+2+10$

$y=-x+12$ ----> equation B

step 3

Find the intersection point equation A and equation B

$y=x+2$ -----> equation A

$y=-x+12$ ----> equation B

solve the system by graphing

The intersection point is (5.7)

see the attached figure

step 4

we know that

The distance from point P to the the line L is equal to the distance between the point P and point (5,7)

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

we have

(2,10) and (5,7)

substitute

$d=\sqrt{(7-10)^{2}+(5-2)^{2}}$

$d=\sqrt{(-3)^{2}+(3)^{2}}$

$d=\sqrt{18}\ units$

simplify

$d=3\sqrt{2}\ units$

see the attached figure to better understand the problem

6 0

3 years ago