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elena55 [62]
3 years ago
9

A surveyor found the angle of elevation from the ground to the top of the building at two locations 20 feet apart as shown below

.
Which measurements are correct? Round side lengths to the nearest hundredth. Check all that apply.
m∠A = 57°
m∠B = 15°
c ≈ 10.89 ft
h ≈ 8.09 ft
h ≈ 31.28 ft

Mathematics
2 answers:
larisa86 [58]3 years ago
8 0

Answer:

Option B and Option E are correct.

Step-by-step explanation:

A surveyor found the angle of elevation from the ground to the top from a point = 33°

Then moves 20 ft towards the building angle of elevation becomes 48°.

Now as per figure attached

m∠A + 48° = 180°

m∠A = 180 - 48 = 132° [∠A and 48° are supplementary to each other]

m∠B + 33° + 132° = 180°

m∠B = 180 - 165° = 15°

\frac{sin33}{c}=\frac{sinB}{20} [sine rule]

\frac{0.5446}{c}=\frac{sin15}{20}=\frac{0.2588}{20}=0.0129

c=\frac{0.5446}{.0129}=42.22

Now sin48=0.7431=\frac{h}{c}=\frac{h}{42.22}

h = 0.7431×42.22 ≈ 31.28 ft

Therefore Option B and Option E are correct.

bixtya [17]3 years ago
7 0
The second and last one are right 
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Answer:

b)  1/32

Step-by-step explanation:

1/2 x 1/2 x 1/2 x 1/2 = 1/32

7 0
2 years ago
On the graph below are three points X, Y, and Z. Write the coordinates for the given dilation.
Julli [10]

ANSWER

( -  \frac{3}{2} , - 1)

EXPLANATION

From the graph, the coordinates of Y are:

(3,2)

We want to find the image of this point after a dilation by a scale factor of -½ about the origin.

The rule for the dilation is :

(x,y)\to( - \frac{1}{2}  x, -  \frac{1}{2} y)

To find the coordinates of Y', we plug the coordinates of Y.

Y(3,2)\to \: Y'( - \frac{1}{2}  (3), -  \frac{1}{2}(2) )

Y(3,2)\to \: Y'( - \frac{3}{2}, - 1)

The first choice is correct.

6 0
3 years ago
HURRYYYYYYYYY!! What is the equation of the quadratic function with a vertex at (2, 25) and an x-intercept at (7,0)?
tangare [24]

Answer:

y=-(x-7)(x+3)

which is none of the choices provided.

Are you sure the question is right or even the choices?

You can even write it as:

y=-(x+3)(x-7) but this is still not a choice.

Step-by-step explanation:

The vertex form of a quadratic is y=a(x-h)^2+k.

This is called vertex form because it gives you the vertex is (h,k).

We are given that (h,k)=(2,25) which makes our equation:

y=a(x-2)^2+25.

We can find the value of a by plugging in the x-intercept (7,0) for (x,y) into:

y=a(x-2)^2+25

0=a(7-2)^2+25

0=a(5)^2+25

Subtract 25 on both sides:

-25=a(5)^2

-25=a(25)

Divide both sides by 25:

\frac{-25}{25}=a

-1=a.

So the equation for the quadratic is:

y=-1(x-2)^2+25

Let's put this into factored form since all the choices are in factored form.

This will require us to multiply the (x-2)(x-2) out:

y=-1(x-2)(x-2)+25

y=-1(x^2-2x-2x+4)+25

y=-1(x^2-4x+4)+25

y=-x^2+4x-4+25

y=-x^2+4x+21

Factor out -1:

y=-(x^2-4x-21)

WE need to find two numbers that multiply to be -21 and add to be -4:

y=-(x-7)(x+3)

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7 0
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