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valkas [14]
3 years ago
15

X^2-3/4x +3/8 equals what

Mathematics
1 answer:
IgorC [24]3 years ago
7 0
Liihjhgfgyhbguijhuihgyijhh
You might be interested in
Quiz
Serjik [45]

Answer:

78

Step-by-step explanation:

5^2 = 25 5^3 = 125 them two added together equals 150

6^2 = 36 so 36 plus 36 equals 72

150-72=78

8 0
3 years ago
Read 2 more answers
Between which two consecutive whole numbers does \sqrt{3} 3 ​ lie? Fill out the sentence below to justify your answer and use yo
lyudmila [28]

Answer:

It lies between 5 and 6

Step-by-step explanation:

Two consecutive numbers are numbers that come after each other:

x , x + 1 are consecutive numbers.

3 \sqrt{3} = 3√3 = 5.19615242271

Therefore, from the above calculation, we can see that square root of 3 is a number that is between consecutive numbers 5 and 6

3 0
3 years ago
QUESTION 8. An unknown number is added to 8. The sum is
Rudik [331]

Answer:

82

Step-by-step explanation:

Let the unknown number be x

If an unknown number is added to 8, this is expressed as;

8 + x

<em>If The sum is  then divided by 9 to give the answer 10, then;</em>

<em>(8+x)/9 = 10</em>

<em>Cross multiply</em>

<em>8 + x = 9 * 10</em>

<em>8 + x = 90</em>

<em>x = 90 - 8</em>

<em>x = 82</em>

Hence the unknown number is 82

3 0
3 years ago
PLSSS? i dont really get it<br> Thanks
solmaris [256]

Answer:

A) 83 km/ hour

B) 2/7 penalties / game

C) $16 / CD

D) 9 donuts / box

Step-by-step explanation:

A)

For this question they are asking for the distance traveled in 1 hour.

Since 747km was travelled in 9 hours, we divide 747 by 9 to find the distance travelled in 1 hour

747 ÷ 9 = 83

The unit rate is 83 km/ hour

B)

You have to find the number of penalties per game

Like before divide 10 by 35:

10 ÷ 35 = 10/35 = 2/7

2/7 penalties / game

C)

Find the cost of 1 CD :

64 / 4 = 16

$16 / CD

D)

Find the amount of donuts per box:

72/8 = 9

9 donuts per box

-Chetan K

3 0
3 years ago
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BEST ANSWER GETS BRANLIEST!
vichka [17]

Answer:

The mean baseball score is 2.5

8 0
3 years ago
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