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katen-ka-za [31]
3 years ago
15

Jason draws a line in the sand at the beach the line is 7/8 feet long he wants to divide the line into sections that are 1 8 fee

t long how many sections with a line be divided into?
Mathematics
2 answers:
abruzzese [7]3 years ago
4 0
The answer is 7 sections
In this type of question, you just need to divide the total length of the line that drawn by Jason with the length of sections that Jason want.

So, the calculation would be:

(7/8) / (1/8)

= 7/8  x 8/1

= 7 amount of sections
OLEGan [10]3 years ago
3 0
The answer is 7 sections
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Need help solving for the midpoint between point a and point b
k0ka [10]

A is located at (-3,-5) B is located at (1,-9)

-3 + 1 = -2/2 =-1

-5 + -9 = -14/2 = -7

 midpoint is (-1,-7)

7 0
3 years ago
A rectangular floor is 6 yards long and 4 yards wide. What is the area of the floor in square feet? Please help!
lys-0071 [83]
Area = length x width

A = L•W

There are 3 feet in one yard.

6 yards = 18 feet

4 yards = 12 feet

A = (18)(12)

A = 216 square feet
8 0
3 years ago
Find, correct to the nearest degree, the three angles of the triangle with the given vertices. A(1, 0, −1), B(4, −3, 0), C(1
zavuch27 [327]

Answer:

Angle at vertex  A : 59.2° B: 61.7° C : 59.1°

Step-by-step explanation:

1. First find the length of the vectors  

AB = B-A = (4-1, 3-0, 0-1) = (3, 3, -1)

AC = C-A = (1-1, 4-0, 3-1) = (0, 4, 2)

BC = C-B = (1-4, 4-3, 3-0) = (-3, 1, 3)

2. Find magnitude of the vectors

|AB| = √(3^2+3^2+〖(-1)〗^2 )=√19  

|AC| = √(0^2+4^2+2^2 )=2√5

|BC| = √(〖(-3)〗^2+1^2+3^2 )=√19

3. Find the angles between them

cos θ = (a.b)/(|a||b|) -----> θ = arc cos ((a.b)/(|a||b|))

AB, AC : θ =arc cos (AB.AC)/(|AB||AC|) = arc cos ( (3.0+3.4+ -1.2)/(√19  x 2√5)=  10/(2√95) ) =59.136, which is approximately 59.14°

AB, BC : θ =arc cos (AB.BC)/(|AB||BC|) = arc cos( (3.-3+3.1+ -1.3)/(√19  x √19)=  (-9)/19 ) = 118.27°

Because of the direction of BC is pointing relative to AB this is the angle outside the triangle, and we should find the supplementary angle.

180-118.27 = 61.73°

If we used –(BC) = CB in the formula (just negate the numerator) we would have gotten the correct angle on first try.

The 3rd angle should be what’s left after subtracting from 180°;

180-61.73-59.14 = 59.13 °

You can confirm using the formula again :

AC, BC : θ =arc cos (AC.BC)/(|AC||BC|) = arc cos( (0.-3+4.1+ 2.3)/(√19  x 2√5)=  10/(2√95) = 59.13°

Rounding everything up so they add up to 180 degrees we have Angle at vertex  A : 59.2° B: 61.7° C : 59.1°

7 0
3 years ago
Help in geometry?????
blagie [28]
D because there are 8 outcomes 
3 0
3 years ago
Read 2 more answers
Combine like terms<br><br> 4y^2+4(7y^2-8)=<br><br> please show your work
kirza4 [7]

Answer:

32y^2-32

Step-by-step explanation:

4y^2+4(7y^2-8)

4y^2+28y^2-32

32y^2-32

if you need extra steeps explaining then plz let me know and I will help :)

8 0
3 years ago
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