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sweet-ann [11.9K]
3 years ago
11

What is the area of this figure? A.49.5 in² B.66.5 in² C.84 in² D.91 in²

Mathematics
2 answers:
Sindrei [870]3 years ago
4 0
The answer should be 91
aliya0001 [1]3 years ago
3 0
The area of a trapezoid with base lengths 7 in and 19 in is given by
  A = (1/2)(b1 + b2)h
  A = (1/2)(7 +19)·7 = 91

The appropriate choice is
  D. 91 in²


_____
It can also be figured by adding the area of the 7 in square (49 in²) to the area of the 7×12 in right triangle (42 in²).
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16. Find the values of x and y.<br> (2y + 5)<br> (5r - 17)<br> (3r - 11)
Alinara [238K]
(5x - 17) + (3x - 11)= 180 [ Linear Pair ]
= 8x - 28= 180
= 8x= 208
= x = 208/8
= x = 26

3x-11
= 3*26 - 11
=67

Now, we have:
(2y+5)+90+(3x-11)=180 [Linear Pair]

Substituting (3x-11),
(2y+5) + 90 + 67= 180
= (2y+5)+157= 180
= 2y + 162= 180
= 2y= 18
=y = 18/2
=y= 9

Therefore, x= 26, and y= 9

Please hit the ‘Thanks’ if this helped

Have a great day.
3 0
3 years ago
Given that f(x) = x2 − 3x + 3 and g(x) = the quantity of x minus one, over four , solve for f(g(x)) when x = 5. (1 point)
Anna007 [38]

Rewrite g(x) as    x-1

                           ------

                              4

and then substitute this result for x in f(x) = x^2 - 3x + 3:

f(g(x)) = (x-1)^2 / 4^2 - 3(x-1)/4 + 3.

At this point we can substitute the value 5 for x:

f(g(5)) = (5-1)^2 / 4^2 - 3(5-1)/4 + 3

          = 16/16 - 3(4/4) + 3 = 1 - 3 + 3 = 1

Therefore, f(g(5)) = 1.

6 0
3 years ago
An island is 1 mi due north of its closest point along a straight shoreline. A visitor is staying at a cabin on the shore that i
Elanso [62]

Answer:

The visitor should run approximately 14.96 mile to minimize the time it takes to reach the island

Step-by-step explanation:

From the question, we have;

The distance of the island from the shoreline = 1 mile

The distance the person is staying from the point on the shoreline = 15 mile

The rate at which the visitor runs = 6 mph

The rate at which the visitor swims = 2.5 mph

Let 'x' represent the distance the person runs, we have;

The distance to swim = \sqrt{(15-x)^2+1^2}

The total time, 't', is given as follows;

t = \dfrac{x}{6} +\dfrac{\sqrt{(15-x)^2+1^2}}{2.5}

The minimum value of 't' is found by differentiating with an online tool, as follows;

\dfrac{dt}{dx}  = \dfrac{d\left(\dfrac{x}{6} +\dfrac{\sqrt{(15-x)^2+1^2}}{2.5}\right)}{dx} =  \dfrac{1}{6} -\dfrac{6 - 0.4\cdot x}{\sqrt{x^2-30\cdot x +226} }

At the maximum/minimum point, we have;

\dfrac{1}{6} -\dfrac{6 - 0.4\cdot x}{\sqrt{x^2-30\cdot x +226} } = 0

Simplifying, with a graphing calculator, we get;

-4.72·x² + 142·x - 1,070 = 0

From which we also get x ≈ 15.04 and x ≈ 0.64956

x ≈ 15.04 mile

Therefore, given that 15.04 mi is 0.04 mi after the point, the distance he should run = 15 mi - 0.04 mi ≈ 14.96 mi

t = \dfrac{14.96}{6} +\dfrac{\sqrt{(15-14.96)^2+1^2}}{2.5} \approx 2..89

Therefore, the distance to run, x ≈ 14.96 mile

6 0
3 years ago
Please help I don’t want to give up it’s getting hard
Svetradugi [14.3K]

Answer:

144 goes with 12, 36 goes with 6, 9 goes with 3, and 121 goes with 11.

Step-by-step explanation:

The second number stated in each phrase is time itself to create the first number. For example, 144. If we take the second number in the number phrase (12) and time it by itself (12 * 12) it equals 144. This applies to each number phrase.

6 0
3 years ago
Read 2 more answers
A veterinary clinic saw 45 pets on Monday. The shaded squares in the grid below represent the 60% of pets
Black_prince [1.1K]
Answer: 27 dogs were seen at the clinic on monday.

27/45 = 0.6

0.6 = 60%
3 0
2 years ago
Read 2 more answers
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