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3 years ago

What is 4 6/8+11 1/3

2 answers:

6 0

So 4 6/8= (32/4)+6/8=38/8
11 1/3=(33/3)+1/3=34/3
so 38/8+(34/3)

to add you must get the bottom number equall so

114/24+272/24=386/24=16 1/12

valkas [14]3 years ago

4 0

Well, first of all you would need to find common denominators. Obviously 8 and 3 have a common denominator of 24, because 8 times 3 equals 24. Now, for the 4 6/8 the whole number (4) would stay the same, but the fraction would turn into 18/24 because you multiplied the denominator by three, and whatever you do to the bottom you must do to the top. For the 11 1/3 it would be 11 8/24 because the whole number (11 would stay the same while, again, you multiply both the top and bottom by 8. So, the problem would turn into 4 18/24 + 11 8/24, which equals 15 26/24. This would then simplify to 18 23/24.

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9 and 5/12 - 3 and 2/3

lana [24]

Recall to always convert the mixed fractions to "improper" fractions first,

$\bf \stackrel{mixed}{9\frac{5}{12}}\implies \cfrac{9\cdot 12+5}{12}\implies \stackrel{improper}{\cfrac{113}{12}}
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\stackrel{mixed}{3\frac{2}{3}}\implies \cfrac{3\cdot 3+2}{3}\implies \stackrel{improper}{\cfrac{11}{3}}\\\\
-------------------------------\\\\
\cfrac{113}{12}-\cfrac{11}{3}\impliedby \textit{clearly our LCD is 12}\implies \cfrac{113-(4)11}{12}
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\cfrac{113-44}{12}\implies \cfrac{69}{12}\implies 5\frac{9}{12}$

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3 years ago

Given the sequence, 26, 13, 6.5, ..... find a) the 10th term and b) the sum of the first 18 terms

Hunter-Best [27]

Answer:

a) 10th term is 0.051

b) The sum of first 18 terms of given sequence is 51.48

Step-by-step explanation:

We are given the sequence 26, 13, 6.5, ..... we need to find

a) 10th term

b) Sum of first 18 terms

Before solving we need to determine if the sequence is arithmetic or geometric

The sequence is arithmetic if common difference d is same.

The sequence is geometric if common ratio r is same.

Finding common difference d: 13-26 = -13, 6.5-13= -6.5

As common difference is not same so, the sequence is not arithmetic.

Finding common ratio r : 13/26 =0.5, 6.5/13= 0.5

As common ratio is same so, the sequence is geometric.

a) Finding common difference: 13-26 = -13, 6.5-13= -6.5

As common difference is not same so, the sequence is not arithmetic.

a) 10th term

The formula to find 10th term is: $a_n=a_1r^{n-1}$

We have a₁=26 and r = 0.5 n=10

$a_n=a_1r^{n-1}\\a_{10}=26(0.5)^{10-1}\\a_{10}=26(0.5)^{9}\\a_{10}=0.051$

So, 10th term is 0.051

b) Sum of first 18 terms

The formula to find sum of geometric series is: $S_n=\frac{a(1-r^n)}{1-r}$

where a= 1st term, r = common ratio and n= number of terms

In the given sequence we have

a=26, r=0.5 and n=18

Finding sum of first 18 terms

$S_n=\frac{a(1-r^n)}{1-r}\\S_{18}=\frac{26(1-(0.5)^{18}}{1-0.5}\\S_{18}=\frac{26(0.99)}{0.5}\\S_{18}=\frac{25.74}{0.5}\\S_{18}=51.48$

So, sum of first 18 terms of given sequence is 51.48

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kifflom [539]

Answer:

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Step-by-step explanation:

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