The resistance would increase.
To solve this problem it is necessary to apply the concepts related to hydrostatic pressure or pressure due to a fluid.
Mathematically this pressure is given under the formula
Where,
= Density
h = Height
g = Gravitational acceleration
Rearranging in terms of g
our values are given as
Replacing we have
Therefore the gravitational acceleration on the planet's surface is 
(Almost the gravity of the Earth)
Answer:
0.695s
Explanation:
From Hooke's law, the restoring force is given has
F = -ky .......1
Where F is the force, y is the spring displacement and k force constant of the spring.
Also recall,
F=mg ............ 2
Where m is the mass of object, g is the acceleration due to gravity.
Equating 1 and 2
Ky = mg
Given that g=9.8m/s2 , y is 3.4cm and g is 8g
K×3.4/100m =8/1000kg × 9.8m/s2
K= ( 0.008kg × 9.8m/s2 ) ÷ 0.034
K= 0.0784÷0.035
K=2.24N/m
Mass ofvthe second object is 25g =0.025kg
Period of oscillation T
T=2π√m/k
T=2×3.142√0.025/2.24
T=6.284√0.0111
T=0.659seconds
Objects can only go so fast and that speed is called terminal velocity. so the answer is A
