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zmey [24]
3 years ago
9

Water flows through a horizontal pipe (from a wider area to narrow area section) and then out into the atmosphere at a speed v1

15 m/s. The diameters of the wide and narrow sections of the pipe are 5.0 cm and 3.0 cm.
What volume of water flows into the atmosphere during a 10 min period?
Physics
1 answer:
Darina [25.2K]3 years ago
4 0

Answer:

V = 6.36 m³

Explanation:

For this exercise we will use fluid mechanics relations, starting with the continuity equation.

Let's write the flow equation

        Q = v₁ A₁

       

The area of ​​a circle is

        A = π r²

Radius is half the diameter

        A = π/4  d²

        Q = v₁ π/4 d₁²

        Q = π/ 4 15 0.03 2

        Q = 0.0106 m3 / s

The volume of water in t = 10 min = 10 60 = 600 s

        Q = V / t

        V = Q t

         V = 0.0106 600

          V = 6.36 m³

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5 0
3 years ago
A bicyclist in the Tour de France crests a mountain pass as he moves at 18 km/h. At the bottom, 4.0 km farther, his speed is at
Allisa [31]

We are given:

v0 = initial velocity = 18 km/h

d = distance = 4 km

v = final velocity = 75 km/h

a =?

<span>
We can solve this problem by using the formula:</span>

v^2 = v0^2 + 2 a d

 

75^2 = 18^2 + 2 (a) * 4

5625 = 324 + 8a

<span>a = 662.625 km/h^2</span>

6 0
3 years ago
You hang a heavy ball with a mass of 30 kg from a tungsten rod 2.8 m long by 1.5 mm by 2.6 mm. You measure the stretch of the ro
guajiro [1.7K]

Answer:

Young's modulus (Y) = 3.56×10^11 N/m^2

The speed of sound in tungsten = 6166.4 m/s

Explanation:

Young's modulus (Y) = stress/strain

Stress = force/area

Force = mg = 30×9.8 = 294 N

Area = 1.5 × 2.6 = 3.9 mm^2 = 3.9/10^6 = 3.9×10^-6 m^2

Stress = 294/3.9×10^-6 = 7.54×10^7 N/m^2

Strain = extension/length

Extension = 0.000594 m

Length = 2.8 m

Strain = 0.000594/2.8 = 2.12×10^-4

Y = 7.54×10^7/2.12×10^-4 = 3.56×10^11 N/m^2

Y = h × rho × g

rho = 18.7 g/cm^3 = 18.7 g/cm^3 × 1 kg/1000 g × (100 cm/1 m)^3 = 18,700 kg/m^3

h = 3.56×10^11/(18,700×9.8) = 1.94×10^6 m

From the equations of motion

v^2 = u^2 + 2gh =

Initial speed (u) = 0 m/s

v = sqrt (2×9.8×1.94×10^6)

v = 6166.4 m/s

7 0
3 years ago
Read 2 more answers
You yell into a canyon. You hear the echo in 3 seconds. How long did the sound of your voice travel before bouncing off a cliff?
Lilit [14]

Answer:

The sound travelled 516 meters before bouncing off a cliff.

Explanation:

The sound is an example of mechanical wave, which means that it needs a medium to propagate itself at constant speed. The time needed to hear the echo is equal to twice the height of the canyon divided by the velocity of sound. In addition, the speed of sound through the air at a temperature of 20 ºC is approximately 344 meters per second. Then, the height of the canyon can be derived from the following kinematic formula:

2\cdot h = v\cdot t (1)

Where:

h - Height, measured in meters.

v - Velocity of sound, measured in meters per second.

t - Time, measured in seconds.

If we know that  v = 344\,\frac{m}{s} and t = 3\,s, then the height of the canyon is:

h = \frac{v\cdot t}{2}

h = \frac{\left(344\,\frac{m}{s} \right)\cdot (3\,s)}{2}

h = 516\,m

The sound travelled 516 meters before bouncing off a cliff.

7 0
2 years ago
Which of the following has the most momentum?
777dan777 [17]

Answer:

0.50 kg moving at 10 m/s

Explanation:

          mv = p

 0.50(10) = 5.0 kg•m/s

5.0(0.50) = 2.5 kg•m/s

         1(2) = 2 kg•m/s

 0.40(10) = 4.0 kg•m/s

5 0
2 years ago
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