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2 years ago

Help please? thank you

Mathematics

1 answer:

Alexxandr [17]2 years ago

8 0

9514 1404 393

Answer:

RS = √(b² +(c -a)²)

Step-by-step explanation:

Put the given point coordinates in the given formula:

R = (x₁, y₁) = (0, a)
S = (x₂, y₂) = (b, c)

RS = √((b -0)² +(c -a)²)

RS = √(b² +(c -a)²)

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(50 POINTS) Math Inverse Functions please help

Afina-wow [57]

Answer:

See below.

Step-by-step explanation:

An inverse function has the x and y coordinates switched. For example, if a function has point (1, 3), then the inverse function has point (3, 1).

Let's find the ordered pairs of the inverse function. We take all the ordered pairs of the original function:

(1, 3), (7, 4), (8, 6), (9, y)

Now we switch x and y in each ordered pair to come up with the inverse function.

The inverse function has these ordered pairs:

(3, 1), (4, 7), (6, 8), (y, 9)

For a relation to be a function, a value used as an x-coordinate can appear only once.

The last ordered pair is (y, 9). For the inverse relation to be a function, y cannot be 3, 4, or 6.

4 0

3 years ago

Read 2 more answers

Which set of ordered pairs that satisfy the equation

krok68 [10]

Answer:

Step-by-step explanation:

5 0

2 years ago

The right expression to calculate how much money will be in an investment account 14 years from now if you deposit $5,000 now an

Svet_ta [14]

Answer:

The expression to compute the amount in the investment account after 14 years is: <em>FV</em> = [5000 ×(1.10)¹⁴] + [3000 ×(1.10)⁸].

Step-by-step explanation:

The formula to compute the future value is:

$FV=PV[1+\frac{r}{100}]^{n}$

PV = Present value

r = interest rate

n = number of periods.

It is provided that $5,000 were deposited now and $3,000 deposited after 6 years at 10% compound interest. The amount of time the money is invested for is 14 years.

The expression to compute the amount in the investment account after 14 years is,

$FV=5000[1+\frac{10}{100}]^{14}+3000[1+\frac{10}{100}]^{14-6}\\FV=5000[1+0.10]^{14}+3000[1+0.10]^{8}$

The future value is:

$FV=5000[1+0.10]^{14}+3000[1+0.10]^{8}\\=18987.50+6430.77\\=25418.27$

Thus, the expression to compute the amount in the investment account after 14 years is: <em>FV</em> = [5000 ×(1.10)¹⁴] + [3000 ×(1.10)⁸].

4 0

3 years ago

The sum of 5 times a larger number and twice a smaller is 5. The difference of 4 times the larger and the smaller number is 4. F

Gemiola [76]

Answer:

1 and 0

Step-by-step explanation:

Let's call the smaller number x and the larger number y.

This means 5y+2x=5.

Also, 4y-x=4.

This is a system of equations. There are two main ways two solve this.

Method 1: Substitution

5y+2x=5

4y-x=4

Solve for one of the variables, then substitute it back into one of the equations to solve for the other variable.

I will take 4y-x=4 and solve for x.

4y=4+x

x=4y-4

Then substitute for x in the other equation and solve for y.

5y+2x=5

5y+2(4y-4)=5

5y+8y-8=5

13y=13

y=1

Now we can go back to our equation for x and substitute for y.

x=4y-4

x=4(1)-4=0

y, the larger number, is 1 and

x, the smaller number, is 0

Method 2: Elimination

5y+2x=5

4y-x=4

Change the equations so that the coefficient of one of the variables in an equation is opposite the one in the other equation. Then add the equations and solve for each variable.

If I multiply both sides of the second equation, 4y-x=4, by 2, the coefficient of x will become -2. In the first equation, the coefficient is 2, so they will become opposites.

4y-x=4

becomes

8y-2x=8

Now we have 5y+2x=5 and 8y-2x=8.

Add the sides of both equations to cancel the x values.

5y+2x+8y-2x=5+8

13y=13

y=1

like last time, we can substitute for y in any of the original equations to get x.

5y+2x=5

5(1)+2x=5

5+2x=5

2x=0

x=0

y, the larger number, is 1 and

x, the smaller number, is 0

6 0

2 years ago

Can someone please help me extra points

Maslowich

Answer:

4) m: 1.25 b: 6 Equation: y= 1.25x + 6

5) m: 20 b: 10 Equation: y= 40x + 10

6) m: -2 b: 0 Equation: y= -2x + 0

7) m: 1/5 b: 1 Equation: y= 1/5x + 1

8) -8.7 = 1.3x + 0

I really hope this helps!

3 0

3 years ago