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olga2289 [7]
4 years ago
9

A movie rental company charges $3 per movie, m, and a monthly fee of $20. What is the equation that represents the cost, C, to r

ent movies from the company for one month
Mathematics
2 answers:
Natali5045456 [20]4 years ago
6 0

Answer:

c = 2m + 20

Step-by-step explanation:

Before anything, let's make sure our variables are defined:

Movie = M

Cost = C

A way to think about this is because we're looking for C and our M value is changing, C = y and M = x. That would make 20 = b, making this C = 3M + 20. (This may or may not make sense, so if it doesn't, just ignore this.)

Ok so the first thing to note is that this is for <u>one month</u>. What does that mean? That means, our $20 monthly fee never changes. It happens once in the equation. So whatever we have, we add $20 to it, once.

The second thing to note is that we don't know how many movies are being rented. But! We already have a variable m for how many movies are being charged. So to find the number of movies, we find $3 * m, or $3m.

Finally, we know how much the monthly fee is and we know how much the movies are, so we add those together to find the total cost:

c = 3m + 20

*Note: Your grader may or may not want $ signs next to each number. It is doubtful they would, and I've never seen it, but just in case, your actual answer would be: $(c = 2m + 20)

OLga [1]4 years ago
4 0

Answer:

3m + 20 = C

Step-by-step explanation:

I Don't know But trust me

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Answer:

They are similar by the definition of similarity in terms of a dilation

Step-by-step explanation:

The given vertices of triangle ΔABC are;

A(1, 5), B(3, 9), and C(5, 3)

The vertices of triangle ΔDEF are;

D(-3, 3), E(-2, 5), and F(-1, 2)

Therefore, we get;

The length of segment, \overline{AB} = √((9 - 5)² + (3 - 1)²) = 2·√5

The length of segment, \overline{BC} = √((9 - 3)² + (3 - 5)²) = 2·√10

The length of segment, \overline{AC} = √((5 - 3)² + (1 - 5)²) = 2·√5

The length of segment, \overline{DE} = √((5 - 3)² + (-2 - (-3))²) = √5

The length of segment, \overline{EF} = √((2 - 5)² + (-1 - (-2))²) = √10

The length of segment, \overline{DF} = √((2 - 3)² + (-1 - (-3))²) = √5

∴ \overline{AB}/\overline{DE} = 2·√5/(√5) = 2

\overline{BC}/\overline{EF} = 2·√10/(√10) = 2

\overline{AC}/\overline{DF} = 2·√5/(√5) = 2

The ratio of their corresponding sides are equal and therefore;

ΔABC and ΔDEF are similar by the definition of similarity in terms of dilation.

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Answer:

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I hope this helped!

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