All categories

3 years ago

I think the answer is 38 but i’m not sure.

Mathematics

1 answer:

garik1379 [7]3 years ago

7 0

I think its 38 but I'm not sure

You might be interested in

Find the product.<br> a.<br> 5d - 79<br> b. 12 ab. 3cd

Solnce55 [7]

Answer:

35dg & 36abcd

Step-by-step explanation:

Multiply 7 times 5 then add the remaining terms for equation 1. For equation 2 multiply 12 by 3 for 36.

6 0

3 years ago

Calculus 2 Master needed, evaluate the indefinite integral of: <img src="https://tex.z-dn.net/?f=%5Cint%5C%28%20%28lnx%29%5E2%7D

viva [34]

Answer:

$\int (\ln(x))^2dx=x(\ln(x)^2-2\ln(x)+2)+C$

Step-by-step explanation:

So we have the indefinite integral:

$\int (\ln(x))^2dx$

This is the same thing as:

$=\int 1\cdot (\ln(x))^2dx$

So, let's do integration by parts.

Let u be (ln(x))². And let dv be (1)dx. Therefore:

$u=(\ln(x))^2\\\text{Find du. Use the chain rule.}\\\frac{du}{dx}=2(\ln(x))\cdot\frac{1}{x}$

Simplify:

$du=\frac{2\ln(x)}{x}dx$

And:

$dv=(1)dx\\v=x$

Therefore:

$\int (\ln(x))^2dx=x\ln(x)^2-\int(x)(\frac{2\ln(x)}{x})dx$

The x cancel:

$=x\ln(x)^2-\int2\ln(x)dx$

Move the 2 to the front:

$=x\ln(x)^2-2\int\ln(x)dx$

(I'm not exactly sure how you got what you got. Perhaps you differentiated incorrectly?)

Now, let's use integrations by parts again for the integral. Similarly, let's put a 1 in front:

$=x\ln(x)^2-2\int 1\cdot\ln(x)dx$

Let u be ln(x) and let dv be (1)dx. Thus:

$u=\ln(x)\\du=\frac{1}{x}dx$

And:

$dv=(1)dx\\v=x$

So:

$=x\ln(x)^2-2(x\ln(x)-\int (x)\frac{1}{x}dx)$

Simplify the integral:

$=x\ln(x)^2-2(x\ln(x)-\int (1)dx)$

Evaluate:

$=x\ln(x)^2-2(x\ln(x)-x)$

Now, we just have to simplify :)

Distribute the -2:

$=x\ln(x)^2-2x\ln(x)+2x$

And if preferred, we can factor out a x:

$=x(\ln(x)^2-2\ln(x)+2)$

And, of course, don't forget about the constant of integration!

$=x(\ln(x)^2-2\ln(x)+2)+C$

And we are done :)

8 0

3 years ago

I am very not smart so can ya'll help me out on this one?

laila [671]

Answer:

H is not a solution

Step-by-step explanation:

plug each point into the equation and see which one does not work.

F(-3,6): 4(-3) + 3(6) = 6, -12 + 18 = 6, 6=6

G(0,2): 4(0) + 3(2) = 6, 6=6

H(1,-2): 4(1) + 3(-2) = 6, 4 - 6 =6, -2=6

J(3,-2): 4(3) + 3(-2) = 6, 12 -6 = 6, 6=6

H is not a solution

5 0

3 years ago

Divde 3/4÷5/7 what was the error 5/7÷3/4=5/7*4/3=20/21

Dmitriy789 [7]

he change 3/4 instead of 5/7

3 0

3 years ago

Answer ASAP please!<br> ………

sasho [114]

Answer:

47.746, answer choice C

Step-by-step explanation:

47.746

7 0

3 years ago