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Nady [450]
2 years ago
11

I think the answer is 38 but i’m not sure.

Mathematics
1 answer:
garik1379 [7]2 years ago
7 0
I think its 38             but I'm not sure                                                       
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What is the distance from C to D?<br><br> A. 5 units<br> B. 1 unit<br> C. 25 units<br> D. 7 units
Vera_Pavlovna [14]

Answer:

Option A

Step-by-step explanation:

According to the distance formula , for any 2 points P & Q whose coordinates are (x¹ , y¹) and (x² , y²) respectively. So ,

PQ = \sqrt{(x^{2} - x^{1} )^{2} + (y^{2} - y^{1})^{2} }

NOTE = HERE x² , y² DOESN'T MEAN THE SQUARES OF x & y . THEY ARE JUST COORDINATES.

According to the question ,

Coordinate of C = (2 , -1)

Coordinate of D = (5 , 3)

Using distance formula ,

CD = \sqrt{(5-2)^{2} + (3 -(-1))^{2} }

=> CD = \sqrt{3^{2} + 4^{2} } = \sqrt{9 + 16} = \sqrt{25} = 5

5 0
3 years ago
Max caught 43 lb of fish in one deep sea fishing trip the fish needed to be equally separated by weight into 5 packages to sell
solmaris [256]
43÷5=8.6   he would put 8.6 lb per bag
6 0
3 years ago
In circle P with mNRQ = 60°, find the angle measure of minor arc NQ
Galina-37 [17]

Given:

m∠NRQ = 60°

To find:

The angle measure of minor arc NQ

Solution:

The inscribed angle is half of the intercepted arc.

$\Rightarrow m\angle NRQ =\frac{1}{2} m(ar NQ)

Multiply by 2 on both sides.

$\Rightarrow 2 \times m\angle NRQ =2 \times \frac{1}{2} m(ar NQ)

$\Rightarrow 2 \ m\angle NRQ =m(ar NQ)

Substitute m∠NRQ = 60°.

$\Rightarrow 2\times 60^\circ=m(ar NQ)

$\Rightarrow 120^\circ=m(ar NQ)

The measure of minor arc NQ is 120°.

8 0
3 years ago
HELP!!!! Find the area. Simplify your answer.<br> 552-9s<br> 3t2+t
Tems11 [23]

Answer:

A = (5s^2t - 9st) (3t + 1)

Step-by-step explanation:

(5s^2 - 9s) (3t^2 + t)

= 15s2t^2 + 5s^2t - 27st^2 - 9st

= 5s2t (3t + 1) - 9st (3t + 1)

= ( 5s^2t - 9st) (3t+1)

6 0
2 years ago
Find the equation of the axis of symmetry and the coordinates of vertex of the functions =2x^2+4x-3
SVEN [57.7K]
Hello,

Find the equation of the axis of symmetry is like find the maximum or minimum point of this function.

f(x)=2x^2+4x-3\\\\\alpha=-\dfrac{b}{2a}=-\dfrac{4}{4}=-1\\\\

The equation of the axis of symmetry is then :   x=-1

\beta=f(\alpha)=2(-1)^2+4(-1)-3=2-4-3=-5

Coordinates of vertex :   (\alpha,\beta)=(-1;-5)
8 0
3 years ago
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