We evaluate f (x) between [0, 2]
 We have then:
 f (x) = x2 + 2x +3
 f (0) = (0) 2 + 2 (0) +3 = 3
 f (1) = (1) 2 + 2 (1) +3 = 6
 f (2) = (2) 2 + 2 (2) +3 = 11
 We observe that the function g between [0, 2] is between 4 and 7
 We observe that the function h is a linear equation whose rate of change is constant and equal to three.
 Answer:
 from least to greatest, by the rate of change of functions over the interval [0, 2] we have:
 g, h, f
        
                    
             
        
        
        
Multiples of 30 : 30,60,90,120,150....
and the first one that 4 goes into evenly is 60
        
                    
             
        
        
        
Answer: 987,654,314,000
Step-by-step explanation:
 
        
                    
             
        
        
        
Answer:
q = (a - r) / b.
Step-by-step explanation:
a = bq + r
bq = a - r
q = (a - r) / b.