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Lubov Fominskaja [6]

3 years ago

7

What are the solutions to the equation?

1 answer:

just olya [345]3 years ago

7 0

Im not 100% sure if the answer is {-5,5} or {-5, -3} but I know it's one of those two

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<img src="https://tex.z-dn.net/?f=5%20%5Ctimes%205" id="TexFormula1" title="5 \times 5" alt="5 \times 5" align="absmiddle" class

Lemur [1.5K]

$25$
is your answer

4 0

3 years ago

Put these in order of size smallest first. 0.1 30% 1/5

Murljashka [212]

0.1 < 0.2 < 0.3

Since 1/5 = 0.2 and 30% = 30/100 wich is 0.3

4 0

3 years ago

Help please this math is hard

Alenkinab [10]

The answer is 10.35 because 63756 times 60 is 3825360 and 5280 times 70 is 369600 and if you divide those two answers it is 10.35

5 0

2 years ago

Which number(s) below belong to the solution set of the inequality? Check all that apply. 3x > 96 A. 32 B. 27 C. 11 D. 16 E.

Ksenya-84 [330]

If 3x>96, dividing both sides by 3 we get that x>32, therefore only E is an acceptable answer

4 0

3 years ago

Read 2 more answers

Square root of 15-x=-3+Square root of 2x+3<br><br> Solve for x

PSYCHO15rus [73]

$
\sqrt{15-x}=-3\sqrt{2x+3}\impliedby \textit{divide by -3}
\\ \quad \\
\cfrac{\sqrt{15-x}}{-3}=\sqrt{2x+3}\impliedby \textit{squares both sides}
\\ \quad \\
\left( \cfrac{\sqrt{15-x}}{-3} \right)^2=(\sqrt{2x+3})^2\implies 
\cfrac{(\sqrt{15-x})^2}{(-3)^2}=(\sqrt{2x+3})^2
\\ \quad \\
\cfrac{15-x}{9}=2x+3\impliedby \textit{multiply both sides by 9}
\\ \quad \\
15-x=18x+27\impliedby \textit{solve for "x"}$

5 0

3 years ago