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3 years ago

5

Which statement are accurate about snow flakes

1 answer:

Pie3 years ago

5 0

Answer:

Snowflakes are made of snow (your question makes no sense)

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For the reaction 3h2(g) + n2(g) 2nh3(g), kc = 9.0 at 350°c. calculate g° at 350°c.

miss Akunina [59]

When ΔG° is the change in Gibbs free energy

So according to ΔG° formula:

ΔG° = - R*T*(㏑K)

here when K = [NH3]^2/[N2][H2]^3 = Kc

and Kc = 9

and when T is the temperature in Kelvin = 350 + 273 = 623 K

and R is the universal gas constant = 8.314 1/mol.K

So by substitution in ΔG° formula:

∴ ΔG° = - 8.314 1/ mol.K * 623 K *㏑(9)

= - 4536

4 0

3 years ago

Como son los recorridos de los oleoductos y gasoductos en argentina?

lesya692 [45]

Answer:

Estoy confundido.Puedes ser un poco especifico sobre tu pregunta?

Explanation:

8 0

3 years ago

Three isotopes of argon occur in nature – 36 18Ar, 38 18Ar, 40 18Ar. Calculate the average atomic mass of argon to two decimal p

likoan [24]

Answer: 3) 39.96 amu

Explanation:

Mass of isotope Ar- 36 = 35.97 amu

% abundance of isotope Ar- 36= 0.337% = $\frac{0.337}{100}=3.37\times 10^{-3}$

Mass of isotope Ar- 38 = 37.96 amu

% abundance of isotope 2 = 0.063 % = $\frac{0.063}{100}=6.3\times 10^{-4}$

Mass of isotope Ar- 40 = 39.96 amu

% abundance of isotope 2 = 99.600 % = $\frac{99.600}{100}=0.996$

Formula used for average atomic mass of an element :

$\text{ Average atomic mass of an element}=\sum(\text{atomic mass of an isotopes}\times {{\text { fractional abundance}})$

$A=\sum[(35.97\times 3.37\times 10^{-3})+(37.96\times 6.3\times 10^{-4})+(39.96\times 0.996)]$

$A=39.96amu$

Therefore, the average atomic mass of argon is 39.96 amu

4 0

4 years ago

Made up of the protons and neutrons, this part or the atom contains nearly all the mass of the atom

Sonja [21]

Answer:

The nucleus

Explanation:

3 0

3 years ago

What elements are present in this formula? : C7H8N4O2, How many atoms of each element are in this molecule? what patterns do you

iragen [17]

carbon, hydrogen, nitrogen, and oxygen. the number infront is how many of each element there are, they are increasing and decreasing

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3 years ago

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