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zhuklara [117]
3 years ago
9

Under which conditions is a reaction spontaneous?Edmentum.

Chemistry
1 answer:
Nadusha1986 [10]3 years ago
3 0

Answer:

<em><u>When ΔS > 0 and ΔH < 0, the process is always spontaneous as written. When ΔS < 0 and ΔH > 0, the process is never spontaneous, but the reverse process is always spontaneous. When ΔS > 0 and ΔH > 0, the process will be spontaneous at </u></em>

Explanation:

What are the best conditions to lead towards a spontaneous reaction? <em><u>high negative enthalpy, high temp, high positive entropy. Your enthalpy is high and negative but your entropy is also negative.</u></em>

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You are asked to perform an experiment. When you perform the experiment you notice the vessel is warming. What type of reaction
Brut [27]

Exothermic type of reaction is taking place because this type of reaction generates heat energy.

<h3>What is exothermic reaction?</h3>

Exothermic reactions refer to those chemical reactions that produce heat energy and release that heat energy to the surrounding environment.

So we can conclude that exothermic type of reaction is taking place because this type of reaction generates heat energy.

Learn more about reaction here: brainly.com/question/26018275

3 0
2 years ago
Both diamond and graphite (i.e. pencil lead) consist of carbon atoms. They are only different in their crystalline structures. O
prisoha [69]

Answer:

Moles of carbon atoms  = 3.33  ×  10^{-6} mol

No. of atoms of C in Diamond  = 2.007 ×   10^{28} atom

Atoms of graphite = 6.27 × 10^{23} Atoms

Explanation:

given data

Cost of 0.2g of diamond = $5000

Cost of 25 g of graphite = $ 2

solution

we know cost of 0.2g of diamond is $ 5000 so that for 1$

if buy 1$ = \frac{0.20}{5000}

1$ = 4.0 × 10^{-5} g Carbon

and Moles of carbon atoms  is express as

Moles of carbon atoms = Given mass of Carbon ÷ atomic mass of C      .........1

Moles of carbon atoms  = 4.0  ×  10^{-5}    g/ 2.0g

Moles of carbon atoms  = 3.33  ×  10^{-6} mol

and

No. of atoms of C in Diamond = No. of moles × Avogadro NO    ..............2

No. of atoms of C in Diamond  = 3.33 ×   10^{-6} mol × 6.022 ×   10^{28}

No. of atoms of C in Diamond  = 2.007 ×   10^{28} atom

Graphite

and wew have given Cost of 25 g of graphite is $2 so for but 1$ we get

for buy $1 = 25÷2  = 12.5 g Of graphite

Moles of graphite = 12.5÷12 = 1.04 mol

Atoms of graphite = 1.04 × 6.022 × 1023

Atoms of graphite = 6.27 × 10^{23} Atoms

6 0
3 years ago
If the mass of the reactants in the chemical reaction was 25.3 grams, what was the mass of the products
Mkey [24]

Answer:

5

Explanation:

5

3 0
3 years ago
A 1.00 g sample of n-hexane (C6H14) undergoes complete combustion with excess O2 in a bomb calorimeter. The temperature of the 1
Nadya [2.5K]

Answer:

-5,921x10⁶J/mol

Explanation:

Internal energy change (ΔU) for the reaction of combustion in the bomb calorimeter is:

ΔU = q calorimeter + q solution

Where:

q calorimeter is Ccal×ΔT (Ccal=4042J/°C) and (ΔT is 29,30°C-22,64°C=<em>6,66°C</em>)

q solution is c×m×ΔT (c= 4.184 J/g°C), (m=1502g H₂O), (ΔT is 29,30°C-22,64°C=<em>6,66°C</em>)

Replacing:

ΔU = 26920J + 41854J = <em>68774 J</em>

This energy is per g of n-hexane, now, per mole of n-hexane:

\frac{68774J}{1gHexane} *\frac{86,1g}{1mol}= -<em>5,921x10⁶J/mol</em>

<em>-negative because the energy is produced-</em>

I hope it helps!

5 0
4 years ago
Read 2 more answers
When 551. mg of a certain molecular compound X are dissolved in 100 g of benzonitrile (CH,CN), the freezing point of the solutio
Ludmilka [50]

Answer:

M1 = 49.04 g/mol

Explanation:

The pure benzonitrile has freezing point -12.8°C. By adding  a nonvolatile compound, the freezing point will be changed, a process called cryoscopy. The freezing point will be reduced. In this case, the new freezing point is -13.4°C. The variation at the temperature can be calculated by the equation:

ΔT = Kc*W*i

Where ΔT is the variation at the freezing temperature (without the solute less with the solute), Kc is the cryoscopy constant (5.34 for benzonitrile), W is the molality, and i the Van't Hoff correction factor, which is 1 for benzonitrile.

((-12.8-(-13.4)) = 5.34*W

5.34W = 0.6

W = 0.1124 mol/kg

W = m1/M1*m2

Where m1 is the mass of the solute (in g), M1 is the molar mass of the solute (in g/mol), and m2 is the mass of the solvent (in kg).

m1 = 0.551 g, m2 = 0.1 kg

0.1124 = 0.551/M1*0.1

0.01124M1 = 0.551

M1 = 49.04 g/mol

7 0
3 years ago
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