For 12:
Since the line y = mx + c is a tangent, then the distance from the centre of the circle to the line is equal to the radius.
Using perpendicular distance:
Squaring both sides, we get:
, as required.
Answer:
We have to multiply 4 with 3 to make it equal to 12.
Step-by-step explanation:
Given the two equations:
In elimination method for solving two linear equations in two variables, one variable is eliminated by making the coefficients of the variable equal to each other and then the equations are subtracted from each other so that only one variable remains.
Here, we have to eliminate .
The coefficients are 6 and 4.
The least common multiple of 6 and 4 is 12.
So, we multiply 6 by 2 to make it equal to 12.
and we have to multiply 4 with 3 to make it equal to 12.
And then the two equation have to be subtracted from each other.
Areashaded=areabigcircle-areasmallcircle
areacircle=pir^2
d/2=r
big diameter=20.4, so radius i 20.4/2=10.2cm
small is 10.8/2=5.4
so
big-small
pi10.2^2-pi5.4^2
pi(104.04-29.16)
pi(74.88)
using 3.14=pi
235.1232 cm^2
answer is B
Answer:
Step-by-step explanation:
The first thing we need to do is set up the problem.
<em>5</em><em> - 2</em><em />
After we do this, we have to combine the whole numbers into the fraction to make an improper fraction.
<em>5</em><em> becomes </em><em> because we get 5 times 10 + 1.</em>
<em>2</em><em> becomes</em><em> because we get 2 times 10 + 8.</em>
After doing this we can subtract and get the answer.
<em>51 - 28 = 23</em>
So the answer is .
B + 9 - 2b = 6
-b = 6 - 9
-b = -3
b = 3
5(j - 4) + j = -8
5j - 20 + j = -8
6j = 12
j = 12/6
j = 2
3d - 5 - 2d = -9
d = -9 + 5
d = -4
hope this helps :)