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Wittaler [7]
3 years ago
9

Write an equation to solve for the number of days it would take to reach 1,000 cases.

Mathematics
1 answer:
Ray Of Light [21]3 years ago
3 0

Answer:

5.2x31 = 161.2

161.2+225=386.2

386.2+540=926.2

1000-926.2=73.8

73.8÷5.2=14.2

So, 14th August

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raketka [301]

Answer: ok LOL thx XD

Step-by-step explanation: BRAINLIEST PLS

8 0
3 years ago
Examine the following steps. Which do you think you might use to prove the identity Tangent (x) = StartFraction tangent (x) + ta
Over [174]

Answer:

The correct options are;

1) Write tan(x + y) as sin(x + y) over cos(x + y)

2) Use the sum identity for sine to rewrite the numerator

3) Use the sum identity for cosine to rewrite the denominator

4) Divide both the numerator and denominator by cos(x)·cos(y)

5) Simplify fractions by dividing out common factors or using the tangent quotient identity

Step-by-step explanation:

Given that the required identity is Tangent (x + y) = (tangent (x) + tangent (y))/(1 - tangent(x) × tangent (y)), we have;

tan(x + y) = sin(x + y)/(cos(x + y))

sin(x + y)/(cos(x + y)) = (Sin(x)·cos(y) + cos(x)·sin(y))/(cos(x)·cos(y) - sin(x)·sin(y))

(Sin(x)·cos(y) + cos(x)·sin(y))/(cos(x)·cos(y) - sin(x)·sin(y)) = (Sin(x)·cos(y) + cos(x)·sin(y))/(cos(x)·cos(y))/(cos(x)·cos(y) - sin(x)·sin(y))/(cos(x)·cos(y))

(Sin(x)·cos(y) + cos(x)·sin(y))/(cos(x)·cos(y))/(cos(x)·cos(y) - sin(x)·sin(y))/(cos(x)·cos(y)) = (tan(x) + tan(y))(1 - tan(x)·tan(y)

∴ tan(x + y) = (tan(x) + tan(y))(1 - tan(x)·tan(y)

6 0
3 years ago
Read 2 more answers
How many times larger is 8 x 10^4 than 2 x 10^2
erma4kov [3.2K]

Answer:

400 times Greater

Step-by-step explanation:

8 x 10^4

10^4 = 10000

10000 x 8 = 80000

2 x 10^2

10^2 = 100

2 x 100 = 200

\frac{80000}{200}= 400

6 0
2 years ago
What is the value of x? Enter your answer, as a decimal, in the box.<br><br> ___ cm
lora16 [44]

Answer

50.6

Step-by-step explanation:

I'm not sure how to do it, but I took the quiz and it said this was the correct answer


6 0
3 years ago
Factor y2 + 10z - 10y - yz
stira [4]
Group and factor
group y's with y's and z's with z's
(y²-10y)+(10z-yz)
factor
y(y-10)+z(10-y)
force undistribute -1
-y(10-y)+z(10-y)
factor
(10-y)(-y+z)
(z-y)(10-y) or
(y-z)(y-10)
6 0
3 years ago
Read 2 more answers
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