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Ket [755]
3 years ago
8

For quadrilaterals having the same perimeter,the area is the largest when the quadrilateral is a ____________.

Mathematics
2 answers:
m_a_m_a [10]3 years ago
8 0

square  

Among all quadrilaterals with the same perimeter, square has the largest area.

alina1380 [7]3 years ago
5 0

It can be shown using calculus that the maximum area is obtained when the quadrilateral is a square.

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What is the slope intercept from the two points (6,-6) and (8,8)
Shtirlitz [24]

Answer:

y=7x+1/7

Step-by-step explanation:

Your points (8,8) and (6, -6) can easily be find the slope using (y2-y1) / (x2-x1)

This slope results in 14/2 or 7.

Find the b-value is simple - plug in your 7 into the equation, y=7x+b, then use an existing point on the line to find the b-value. In this case, I used the (8, 8) point.

After plugging in, simply divide to get numbers on the opposite side of variable, and you will end up with 1/7.

The equation turns out to be y=7x+1/7.

5 0
3 years ago
Solve for x. 10x^2=29x-21 does anyone know this
Natasha2012 [34]
10x^2=29x-21 \\
10x^2-29x+21=0\\
\Delta=(-29)^2-4\cdot10\cdot21=841-840=1\\
\sqrt{\Delta}=\sqrt1=1\\
x_1=\frac{-(-29)-1}{2\cdot10}=\frac{28}{20}=\frac{7}{5}\\
x_2=\frac{-(-29)+1}{2\cdot10}=\frac{30}{20}=\frac{3}{2}\\
4 0
3 years ago
What’s the answer? QUICK
Maksim231197 [3]

Answer:

Step-by-step explanation:

4 and 1/6

5 0
3 years ago
Prove that (n+5)^2 - (n+3)^2 is a multiple of 4 for all positive integer values of n.
Drupady [299]

Answer:

(n+5)² - (n+3)² =

= (n² + 10n + 25) - (n² + 6n + 9)

= n² + 10n + 25 - n² - 6n - 9

= 4n + 16

= 4(n + 4) ⋮ 4

3 0
3 years ago
(-241) - (+356) + (-5)
gulaghasi [49]
The answer would come to -602
3 0
3 years ago
Read 2 more answers
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