Question

For triangle ABC, angle A=110, angle B=43, and side b=15. Find side c.

Answer 1

Answer: 10

Step-by-step explanation:

First, find m∠C by using the Triangle Sum Theorem:

∠A + ∠B + ∠C = 180°

110 + 43 + ∠C = 180°

     153   + ∠C = 180°

                ∠C = 27°

Next, Use the Law of Sines to solve for c:

$\dfrac{b}{sin\ B}= \dfrac{c}{sin\ C}$

$\dfrac{15}{sin\ 43}= \dfrac{c}{sin\ 27}$

$\dfrac{15\ sin\ 27}{sin\ 43}= c$

$10 = c$