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3 years ago

What distance will a car traveling at a speed of 30m/s cover in 60 s?

Mathematics

2 answers:

AnnZ [28]3 years ago

6 0

Answer:

1800 m/s if I'm not mistaken! :))

Step-by-step explanation:

allochka39001 [22]3 years ago

4 0

1800 m/s I could be wrong though

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In golf, a score of 0 is called even par. A score of 2 under par is written as -2. A score of 4 over par is written as +4 or 4.

patriot [66]

6 under par is written as -6

2 over par is written as 2

even par is written as 0

Total score: add all the numbers together:

-6 + 2 + 0 + 0 = -4 ( 4 under par).

7 0

3 years ago

Please I need help and thx<br>please show how you did it

rosijanka [135]

Answer:

1.) 9.2

2.)

625

633

the dealer

8.81

Step-by-step explanation:

I'm gonna assume that cm= compounded monthly

1.)

effective rate: .153/12= .01275

x= payments

$2590.67=300*\frac{1-(1+.01275)^{-x}}{.01275}\\.110103476=1-1.01275^{-x}\\.889896525=1.01275^{-x}\\\log_{1.01275}.889896525=-x\\x=9.207$

2.)

If there is no interest rate attached to financing through the deal the payment is just

37500/60 = 625

The monthly payment from the bank has a present value of 37500-3000=34500

and the effective rate is .039/12= .00325

$34500=x\frac{1-(1.00325)^{-60}}{.00325}\\34500=54.43234738x\\x=633.81$

Finally, the amount we save is just the difference

633.81-625=8.81

6 0

3 years ago

Read 2 more answers

Two boats depart from a port located at (–8, 1) in a coordinate system measured in kilometers and travel in a positive x-directi

miss Akunina [59]

Answer:

$\left\{\begin{array}{l}y=-\dfrac{1}{9}x^2 +\dfrac{2}{9}x+\dfrac{89}{9}\\ \\y=\dfrac{1}{8}x^2 -7\end{array}\right.$

Step-by-step explanation:

1st boat:

Parabola equation:

$y=ax^2 +bx+c$

The x-coordinate of the vertex:

$x_v=-\dfrac{b}{2a}\Rightarrow -\dfrac{b}{2a}=1\\ \\b=-2a$

Equation:

$y=ax^2 -2ax+c$

The y-coordinate of the vertex:

$y_v=a\cdot 1^2-2a\cdot 1+c\Rightarrow a-2a+c=10\\ \\c-a=10$

Parabola passes through the point (-8,1), so

$1=a\cdot (-8)^2-2a\cdot (-8)+c\\ \\80a+c=1$

Solve:

$c=10+a\\ \\80a+10+a=1\\ \\81a=-9\\ \\a=-\dfrac{1}{9}\\ \\b=-2a=\dfrac{2}{9}\\ \\c=10-\dfrac{1}{9}=\dfrac{89}{9}$

Parabola equation:

$y=-\dfrac{1}{9}x^2 +\dfrac{2}{9}x+\dfrac{89}{9}$

2nd boat:

Parabola equation:

$y=ax^2 +bx+c$

The x-coordinate of the vertex:

$x_v=-\dfrac{b}{2a}\Rightarrow -\dfrac{b}{2a}=0\\ \\b=0$

Equation:

$y=ax^2+c$

The y-coordinate of the vertex:

$y_v=a\cdot 0^2+c\Rightarrow c=-7$

Parabola passes through the point (-8,1), so

$1=a\cdot (-8)^2-7\\ \\64a-7=1$

Solve:

$a=-\dfrac{1}{8}\\ \\b=0\\ \\c=-7$

Parabola equation:

$y=\dfrac{1}{8}x^2 -7$

System of two equations:

$\left\{\begin{array}{l}y=-\dfrac{1}{9}x^2 +\dfrac{2}{9}x+\dfrac{89}{9}\\ \\y=\dfrac{1}{8}x^2 -7\end{array}\right.$

7 0

4 years ago

Read 2 more answers

The following table shows the number of feet a bird flies above the ground as a function of time: (In the picture)

Otrada [13]

Answer:

D.) (14, 0); the time it takes for the bird to reach the ground

Step-by-step explanation:

The attached graph shows a plot of the table values and the two offered solution options.

The dependent variable in this scenario is the bird's height above the ground. When that is zero, the bird is on the ground. This fact makes choices B and C seem ridiculous.

We note from the table and graph that the bird is on a path that decreases in height by 3 feet every 2 seconds. If the bird continues that rate of descent, it will reach the ground after 14 seconds.

That is, its (time, height) pair will be (14, 0), matching choice D.

_____

Choosing any answer to this question requires making assumptions that are inconsistent with real-world bird behavior. At least, the problem statement should say what assumptions are applicable.

4 0

3 years ago

Read 2 more answers

Please helpppp !!!!!!!!!!!! Will<br> Mark Brianliest !!!!!!!!!!!!!!!!!!!!

Alexxx [7]

Answer:

Step-by-step explanation:

7 0

3 years ago