All categories

3 years ago

Which of the following describes how to translate the graph y = |x| to obtain the graph of y = |x + 1| + 1?

2 answers:

5 0

You would shift one unit left and one unit up using the formula y=mx+b the b is the y coordinate and the number added or subtracted from the x is the coordinate

Xelga [282]3 years ago

5 0

Answer:

2nd Option is correct.

Step-by-step explanation:

Parent function: y = |x|

After translation Obtained Function: y = | x + 1 | + 1

We need to find translation done to get 2nd function.

We know that if we have,

Parental function: y = f(x)

Function we get y = f( x - a ) + b

Translation done here, a unit shifted right and b unit shifted upward.

So,

y = | x - (-1) | + 1

Translation done here is 1 unit left because value of a = -1 and 1 unit upward because 1 is added to f(x).

Therefore, 2nd Option is correct.

You might be interested in

A survey revealed that 56% of the students at North Valley high school are involved with in a sports team. The survey also showe

oksano4ka [1.4K]

Answer:

The probability that a student who is involved in a sports team also participated in the prom dance = 0.1344

Step-by-step explanation:

56% of the students are involved in a sport team

56% = 0.56

According to the question, it is stated that 24% of the students at the school that are involved in a sports team also participated in the prom dance.

24% = 0.24

This means that we are going to find 24% of the original 56%, since 24% of them also participated in the prom dance.

The probability that a student who is involved in a sports team also participated in the prom dance = 0.24 * 0.56

The probability that a student who is involved in a sports team also participated in the prom dance = 0.1344

5 0

3 years ago

Please help i don’t know properties for shi

Lady bird [3.3K]

Answer:

18. Commutative property of addition

19. Distributive property

20. Associative property of addition

Step-by-step explanation:

3 0

2 years ago

I need help immediately!!

mezya [45]

F(4)=4(4)+5
Which equals
F(4)=21

4 0

2 years ago

Read 2 more answers

Bill deposits $3,000 into an account that pays simple interest at a rate of 3% per year. How much interest will he be paid in th

Sholpan [36]

Answer:

The interest he will be paid in the first 4 years is $360

Step-by-step explanation:

The rule of the simple interest is I = Prt, where

P is the initial deposit

r is the rate in decimal

t is the time

∵ Bill deposits $3,000 into an account

∴ P = 3000

∵ The account pays simple interest at a rate of 3% per year

∴ r = 3% = 3 ÷ 100 = 0.03

∵ The time is 4 years

∴ t = 4

→ Substitute these values in the rule above

∵ I = 3000(0.03)(4)

∴ I = 360 dollars

∴ The interest he will be paid in the first 4 years is $360

6 0

3 years ago

A random sample of 36 students at a community college showed an average age of 25 years. Assume the ages of all students at the

Pavel [41]

Answer:

98% confidence interval for the average age of all students is [24.302 , 25.698]

Step-by-step explanation:

We are given that a random sample of 36 students at a community college showed an average age of 25 years.

Also, assuming that the ages of all students at the college are normally distributed with a standard deviation of 1.8 years.

So, the pivotal quantity for 98% confidence interval for the average age is given by;

P.Q. = $\frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample average age = 25 years

$\sigma$ = population standard deviation = 1.8 years

n = sample of students = 36

$\mu$ = population average age

So, 98% confidence interval for the average age, $\mu$ is ;

P(-2.3263 < N(0,1) < 2.3263) = 0.98

P(-2.3263 < $\frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } }$ < 2.3263) = 0.98

P( $-2.3263 \times {\frac{\sigma}{\sqrt{n} }$ < ${\bar X - \mu}$ < $2.3263 \times {\frac{\sigma}{\sqrt{n} }$ ) = 0.98

P( $\bar X - 2.3263 \times {\frac{\sigma}{\sqrt{n} }$ < $\mu$ < $\bar X +2.3263 \times {\frac{\sigma}{\sqrt{n} }$ ) = 0.98

98% confidence interval for $\mu$ = [ $\bar X - 2.3263 \times {\frac{\sigma}{\sqrt{n} }$ , $\bar X +2.3263 \times {\frac{\sigma}{\sqrt{n} }$ ]

= [ $25 - 2.3263 \times {\frac{1.8}{\sqrt{36} }$ , $25 + 2.3263 \times {\frac{1.8}{\sqrt{36} }$ ]

= [24.302 , 25.698]

Therefore, 98% confidence interval for the average age of all students at this college is [24.302 , 25.698].

8 0

3 years ago