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lord [1]
3 years ago
5

Find the value of the expression

Mathematics
1 answer:
Yuri [45]3 years ago
6 0

Answer:

18.5

Step-by-step explanation:

3 + 16 - 2 · 1 ÷ 4

3 + 16 - .5

19 - .5

= 18.5

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4 0
3 years ago
The length of a photograph is 3cm less than twice the width. The area is 54cm^2. Find the dimensions of the photograph.
REY [17]
W= width
l= length= 2w-3

Area= length * width
A= lw
substitute l=2w-3 for l
54= (2w-3)(w)
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subtract 54 from both sides
0= 2w^2 - 3w - 54
factor the polynomial
0= (2w + 9)(w - 6)

Set each set of parentheses equal
to 0 and solve for width.

0=2w+9
-9=2w
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0=w-6
6 cm=w

-4.5 is not the answer because it has a negative value. You cannot have a negative side of a photograph. So substitute 6 in to find length.

length= 2w-3
l= 2(6)-3
l= 12-3
l= 9 cm

CHECK:
w= 6cm
l= 9cm
Area= length * width
54= 6*9
54= 54

ANSWER: width= 6cm; length= 9cm

Hope this helps! :)
4 0
3 years ago
Divide. use base-ten blocks. 72÷5
Sveta_85 [38]

Answer:

14.4

Step-by-step explanation:


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