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ioda
3 years ago
12

keli wants to sew trim around the sleeves and hem of a dance costume. she needs a piece of trim that is 8 1/8 inches long for th

e sleeves and a piece that is 40 5/8 inches long for the hem. if the package contains 5 feet of trim, how much trim will be left after making the costume
Mathematics
2 answers:
damaskus [11]3 years ago
5 0
Bhwjwjwjwjjwjwjwjwjwkwkkw
Sav [38]3 years ago
3 0

Answer:

1 15/16 ft

Step-by-step explanation:

40 5/8 + 8 1/8 = 48 6/8

There are 12 inches in a foot.

48/12 = 4

6/8 inch divided by 12 is 1/16 ft

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Answer:

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Step-by-step explanation:

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<h3>Given Points:</h3>

(-6, 14) and (2, -18)

<h3>To Find:</h3>

The slope of the line that passes through the point.

<h3>Slope Formula:</h3>

y2 - y1 / x2 - x1

<h3>Solution:</h3>

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3 years ago
Determine x when y =144?
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8 0
4 years ago
Alistair and Jason both deposited $500 into their bank accounts. Alistair earned 2.5% simple interest per year. Jason earned 4.5
Vinil7 [7]

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Step-by-step explanation:

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3 years ago
Solve y" + y = tet, y(0) = 0, y'(0) = 0 using Laplace transforms.
irina1246 [14]

Answer:

The solution of the diferential equation is:

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Step-by-step explanation:

Given y" + y = te^{t}; y(0) = 0 ; y'(0) = 0

We need to use the Laplace transform to solve it.

ℒ[y" + y]=ℒ[te^{t}]

ℒ[y"]+ℒ[y]=ℒ[te^{t}]

By using the Table of Laplace Transform we get:

ℒ[y"]=s²·ℒ[y]+s·y(0)-y'(0)=s²·Y(s)

ℒ[y]=Y(s)

ℒ[te^{t}]=\frac{1}{(s-1)^{2}}

So, the transformation is equal to:

s²·Y(s)+Y(s)=\frac{1}{(s-1)^{2}}

(s²+1)·Y(s)=\frac{1}{(s-1)^{2}}

Y(s)=\frac{1}{(s^{2}+1)(s-1)^{2}}

To be able to separate in terms, we use the partial fraction method:

\frac{1}{(s^{2}+1)(s-1)^{2}}=\frac{As+B}{s^{2}+1} +\frac{C}{s-1}+\frac{D}{(s-1)^2}

1=(As+B)(s-1)² + C(s-1)(s²+1)+ D(s²+1)

The equation is reduced to:

1=s³(A+C)+s²(B-2A-C+D)+s(A-2B+C)+(B+D-C)

With the previous equation we can make an equation system of 4 variables.

The system is given by:

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B+D-C=1

The solution of the system is:

A=1/2 ; B=0 ; C=-1/2 ; D=1/2

Therefore, Y(s) is equal to:

Y(s)=\frac{s}{2(s^{2} +1)} -\frac{1}{2(s-1)} +\frac{1}{2(s-1)^{2}}

By using the inverse of the Laplace transform:

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y(t)=\frac{1}{2}cos(t)- \frac{1}{2}e^{t}+\frac{t}{2} e^{t}

8 0
3 years ago
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