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3 years ago

I need help ASAP im very confused on the box part I put the two on the top but then what else?

Mathematics

2 answers:

r-ruslan [8.4K]3 years ago

8 0

Answer is in the file below

tinyurl.com/wpazsebu

fredd [130]3 years ago

7 0

Answer:

See Below

Step-by-step explanation:

for x put in 0, 1 ,2 ,3 ,4

for y, put each x into the equation

if x=0 then

y= 2(0)-5 y= 0-5 y=-5

y=2(1) -5 y= 2-5 y=-3

y= 2(2)-5 y=4-5 y=-1

y = 2(3)-5 y=6-5 y= 1

y= 2(4) -5 y=8-5 y=3

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Simplify this exponent<br> 3^-2

mylen [45]

Answer:

1/9 or .11111111111111111111111111111111111111...

Step-by-step explanation:

The power of two means that it will be 9, but the negative power means it will be the denominator and 1 will be the numerator (top number).

8 0

3 years ago

Angelina factored (x - 48 ) and wrote that it was equal to (x^2 - 4^2)^2(x^2 + 4^2). Use complete sentences to explain how you c

defon

(x^2 - 4^2)^2 = x^4 - 4^4
(x^4 - 4^4) (x^2 + 4^2) = x^2 - 4^6
The Angela's solution is wrong cause when you multiply you get a different answer.

7 0

3 years ago

Suppose a simple random sample of size nequals81 is obtained from a population with mu equals 79 and sigma equals 18. (a) Descr

Daniel [21]

Answer:

(a) The sampling distribution of $\overline{X}$ = Population mean = 79

(b) P ( $\overline{X}$ greater than 81.2 ) = 0.1357

(c) P ( $\overline{X}$ less than or equals 74.4 ) = .0107

(d) P (77.6 less than $\overline{X}$ less than 83.2 ) = .7401

Step-by-step explanation:

Given -

Sample size ( n ) = 81

Population mean $(\nu)$ = 79

Standard deviation $(\sigma )$ = 18

(a) Describe the sampling distribution of $\overline{X}$

For large sample using central limit theorem

the sampling distribution of $\overline{X}$ = Population mean = 79

(b) What is Upper P ( $\overline{X}$ greater than 81.2 ) =

$P(\overline{X}> 81.2)$ = $P(\frac{\overline{X} - \nu }{\frac{\sigma }{\sqrt{n}}}> \frac{81.2 - 79}{\frac{18}{\sqrt{81}}})$

= $P(Z> 1.1)$

= $1 - P(Z< 1.1)$

= 1 - .8643 =

= 0.1357

$P(\overline{X}\leq 74.4)$ = $P(\frac{\overline{X} - \nu }{\frac{\sigma }{\sqrt{n}}}\leq \frac{74.4- 79}{\frac{18}{\sqrt{81}}})$

= $P(Z\leq -2.3)$

= .0107

(d) What is Upper P (77.6 less than $\overline{X}$ less than 83.2 ) =

$P(77.6< \overline{X}< 83.2)$ = $P(\frac{77.6- 79}{\frac{18}{\sqrt{81}}})< P(\frac{\overline{X} - \nu }{\frac{\sigma }{\sqrt{n}}}\leq \frac{83.2- 79}{\frac{18}{\sqrt{81}}})$

= $P(- 0.7< Z< 2.1)$

= $(Z< 2.1) - (Z< -0.7)$

= 0.9821 - .2420

= 0.7401

3 0

3 years ago

Please Help, this is math problems

MariettaO [177]

Answer:

1/8 for the first one then 1/6 for the second one

Step-by-step explanation:

5 0

3 years ago

If my diameter is 19 inches what is my radius

Masja [62]

Answer:

Step-by-step explanation:

To find the radius of a circle you multiply the diameter by 38

(to find the diameter, you divide the radius by 2)

4 0

3 years ago

I need help ASAP im very confused on the box part I put the two on the top but then what else?​

I need help ASAP im very confused on the box part I put the two on the top but then what else?