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2 years ago

Find the function h(x) = f(x) ∘ g(x) if f(x) = x(2 - x) and g(x) = 3x.

1 answer:

4 0

F(x) = x(2 - x)
g(x) = 3x
Substitute 3x for x in the function f(x)

h(x) = f(x) <span>∘ g(x) = f(g(x)) = 3x(2 - 3x)
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3 years ago

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**The equation is not clear, so I have provided both options**

<h3><u>Option 1</u></h3>

$\left|0.3-\dfrac{3}{5}k\right|-0.4=1.2$

$\implies \left|0.3-\dfrac{3}{5}k\right|=1.6$

<u>Solution 1</u>

$\implies 0.3-\dfrac{3}{5}k=1.6$

$\implies -\dfrac{3}{5}k=1.3$

$\implies k=-\dfrac{13}{6}$

<u>Solution 2</u>

$\implies -(0.3-\dfrac{3}{5}k)=1.6$

$\implies -0.3+\dfrac{3}{5}k=1.6$

$\implies \dfrac{3}{5}k=1.9$

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<h3><u>Option 2</u></h3>

$\left|0.3-\dfrac{3}{5k}\right|-0.4=1.2$

$\implies \left|0.3-\dfrac{3}{5k}\right|=1.6$

<u>Solution 1</u>

$\implies 0.3-\dfrac{3}{5k}=1.6$

$\implies -\dfrac{3}{5k}=1.3$

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$\implies k=-\dfrac{6}{13}$

<u>Solution 2</u>

$\implies -(0.3-\dfrac{3}{5k})=1.6$

$\implies -0.3+\dfrac{3}{5k}=1.6$

$\implies \dfrac{3}{5k}=1.9$

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$\implies k=\dfrac{6}{19}$

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