Answer:
v = -9
Step-by-step explanation:
ur welcome
Answer:
85
Step-by-step explanation:
0.350 L × n = 30 L . . . . . where n is the number of bottles.
Divide by 0.350:
n = (30 L)/(0.350 L) ≈ 85.7
85 bottles can be filled, and one can be partially filled.
_____
Of course, you know the SI prefix milli- means 1/1000, so 350 mL = 350/1000 L = 0.350 L. When you do the division indicated above, ...
(30 L)/(0.350 L)
the units of liters cancel, and you are left with the number of bottles.
Answer: t-half = ln(2) / λ ≈ 0.693 / λExplanation:The question is incomplete, so I did some research and found the complete question in internet.
The complete question is:
Suppose a radioactive sample initially contains
N0unstable nuclei. These nuclei will decay into stable
nuclei, and as they do, the number of unstable nuclei that remain,
N(t), will decrease with time. Although there is
no way for us to predict exactly when any one nucleus will decay,
we can write down an expression for the total number of unstable
nuclei that remain after a time t:
N(t)=No e−λt,
where λ is known as the decay constant. Note
that at t=0, N(t)=No, the
original number of unstable nuclei. N(t)
decreases exponentially with time, and as t approaches
infinity, the number of unstable nuclei that remain approaches
zero.
Part (A) Since at t=0,
N(t)=No, and at t=∞,
N(t)=0, there must be some time between zero and
infinity at which exactly half of the original number of nuclei
remain. Find an expression for this time, t half.
Express your answer in terms of N0 and/or
λ.
Answer:
1) Equation given:
← I used α instead of λ just for editing facility..
Where No is the initial number of nuclei.
2) Half of the initial number of nuclei:
N (t-half) = No / 2So, replace in the given equation:
3) Solving for α (remember α is λ)
αt ≈ 0.693
⇒ t = ln (2) / α ≈ 0.693 / α ← final answer when you change α for λ
Answer:
6(x+4)=30
6x+24=30
6x+24-24=30-24
x=6/6
x=1
Step-by-step explanation:
Hope this helps you
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Answer: p = −15
Step-by-step explanation:
Add 11p to both sides.
−10p+11p=−11p−15+11p
p=−15