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sveticcg [70]
3 years ago
11

Can someone please help

Mathematics
2 answers:
DIA [1.3K]3 years ago
8 0
I think C is right because $12.54<$12.79
valina [46]3 years ago
7 0
C IS THE CORRECT ANSWER




GOOD LUCK
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-26 =3v +1 can i please get a answer
garik1379 [7]

Answer:

v = -9

Step-by-step explanation:

ur welcome

5 0
3 years ago
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Fill 350 milliliter bottles from a 30 liter drum how many bottles
Mama L [17]

Answer:

  85

Step-by-step explanation:

0.350 L × n = 30 L . . . . . where n is the number of bottles.

Divide by 0.350:

  n = (30 L)/(0.350 L) ≈ 85.7

85 bottles can be filled, and one can be partially filled.

_____

Of course, you know the SI prefix milli- means 1/1000, so 350 mL = 350/1000 L = 0.350 L. When you do the division indicated above, ...

  (30 L)/(0.350 L)

the units of liters cancel, and you are left with the number of bottles.

6 0
3 years ago
Since at t=0, n(t)=n0, and at t=∞, n(t)=0, there must be some time between zero and infinity at which exactly half of the origin
Airida [17]
Answer: t-half = ln(2) / λ ≈ 0.693 / λ

Explanation:

The question is incomplete, so I did some research and found the complete question in internet.

The complete question is:

Suppose a radioactive sample initially contains N0unstable nuclei. These nuclei will decay into stable nuclei, and as they do, the number of unstable nuclei that remain, N(t), will decrease with time. Although there is no way for us to predict exactly when any one nucleus will decay, we can write down an expression for the total number of unstable nuclei that remain after a time t:

N(t)=No e−λt,

where λ is known as the decay constant. Note that at t=0, N(t)=No, the original number of unstable nuclei. N(t) decreases exponentially with time, and as t approaches infinity, the number of unstable nuclei that remain approaches zero.

Part (A) Since at t=0, N(t)=No, and at t=∞, N(t)=0, there must be some time between zero and infinity at which exactly half of the original number of nuclei remain. Find an expression for this time, t half.

Express your answer in terms of N0 and/or λ.

Answer:

1) Equation given:

N(t)=N _{0} e^{-  \alpha  t} ← I used α instead of λ just for editing facility..

Where No is the initial number of nuclei.

2) Half of the initial number of nuclei: N (t-half) =  No / 2

So, replace in the given equation:

N_{t-half} =  N_{0} /2 =  N_{0}  e^{- \alpha t}

3) Solving for α (remember α is λ)

\frac{1}{2} =  e^{- \alpha t} &#10;&#10;2 =   e^{ \alpha t} &#10;&#10; \alpha t = ln(2)

αt ≈ 0.693

⇒ t = ln (2) / α ≈ 0.693 / α ← final answer when you change α for λ




4 0
3 years ago
Can some one please help me <br><br>solve: 6(x+4) = 30
DochEvi [55]

Answer:

6(x+4)=30

6x+24=30

6x+24-24=30-24

x=6/6

x=1

Step-by-step explanation:

Hope this helps you

Mark me as brainliest

4 0
3 years ago
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–10p = –11p − 15<br> What is the answer
tensa zangetsu [6.8K]

Answer: p = −15

Step-by-step explanation:

Add 11p to both sides.

−10p+11p=−11p−15+11p

p=−15

4 0
3 years ago
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