It’s the first answer, both expressions equal 5 when substituting 2 for x because the expressions are equivalent.
1/2 of x +4
=1/2(2)=1.
1+4= 5
2+6=8
1/2(2)=1.
8-1=7
7-2=5
Answer:
About 7.2 OR (7.211102551)
Step-by-step explanation:
Answer:
Miguel has $63
Lisbeth has $11
David has $21
Step-by-step explanation:
let Miguel share be M
let Lisbeth share be L
let David share be D
from the question, we know that
M=3D
L=D-10.
M+L+D=95
thus,
3D+(D-10)+D= 95
3D+D-10+D= 95
5D-10 = 95
5D= 95+10
5D= 105
D= 105/5
D= 21.
thus,
M = 3D = 3×21
= $63
L = D-10 = 21-10
= $11
(63+21+11)$ = $95
Answer: 49.85%
Step-by-step explanation:
Given : The physical plant at the main campus of a large state university recieves daily requests to replace florecent lightbulbs. The distribution of the number of daily requests is bell-shaped ( normal distribution ) and has a mean of 61 and a standard deviation of 9.
i.e.
and 
To find : The approximate percentage of lightbulb replacement requests numbering between 34 and 61.
i.e. The approximate percentage of lightbulb replacement requests numbering between 34 and
.
i.e. i.e. The approximate percentage of lightbulb replacement requests numbering between
and
. (1)
According to the 68-95-99.7 rule, about 99.7% of the population lies within 3 standard deviations from the mean.
i.e. about 49.85% of the population lies below 3 standard deviations from mean and 49.85% of the population lies above 3 standard deviations from mean.
i.e.,The approximate percentage of lightbulb replacement requests numbering between
and
= 49.85%
⇒ The approximate percentage of lightbulb replacement requests numbering between 34 and 61.= 49.85%
We have been given that on the day of his 18th birthday Harry decided to start saving money regularly
. Starting on that day, he could save 30.00 on the same date every month. We are asked to find the amount saved by the day before Harry's 60th birthday.
First of all, we will find years from 18 years to 60 years.

We know that 1 year equals 12 months.

To find total amount saved, we will multiply 504 months by amount saved per month.


Therefore, Harry would have saved
by the day before his 60th birthday.