Let r(cos O + i sin O) be a cube root of 125(cos 288 + i sin 288)
then
r^3(cos O + i sin O)^3 = 125(cos 288 + i sin 28)
so r^3 = 125 and cos 3O + i sin 3O = cos 288 + i sin 288
so r = 5 and 3O = 288 + 360p and O = 96 + 120p
so one cube root is 5 (cos 96 + i sin 96)
Im a little rusty at this stuff Its been a long time.
Im not sure of the other 2 roots
sorry cant help you any more
2 and 3
negative numbers won't work, nor will 0
1 and 2 won't work because 1*8=2*4
2 and 3 is the answer
Answer:
4900/44829, 293/70
Step-by-step explanation:
Answer:
96 because it's the same length but just slanted
