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Arlecino [84]
3 years ago
14

What is an equation of the like with a slope of 1/4 and a y intercept of -2

Mathematics
2 answers:
gladu [14]3 years ago
7 0
Y= 1/4x -2 is the answer to that
SVEN [57.7K]3 years ago
3 0
Y = mx + c is the general equation of a line. m is the slope and c is the y intercept, by substituting these values in you get y = 1/4 x -2
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Solve the system by substitution.<br>3x-6y=2<br>4x+3y=-1​
crimeas [40]

Answer:

y = -1/3

x = 0

Step-by-step explanation:

3x-6y = 2    then 3x = 2+6y,   x=(2+6y)/3

4x+3y = -1

substitute for x

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reduce

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8 0
3 years ago
The function f determines the cost (in dollars) of a new Honda Accord in terms of the number of years t since 2000. That is, f (
xenn [34]

Complete  Question

The function f determines the cost (in dollars) of a new Honda Accord in terms of the number of years t since 2000. That is, f ( t ) represents the cost (in dollars) of a new Honda Accord t years after 2000. Use function notation to represent each of the following. The cost (in dollars) of a new Accord in 2006?

A. How much more a new Accord costs in 2013 as compared to the cost of a new Accord in 2010?

B. A new Accord in 2013 is how many times as expensive as a new Accord in 2010?

C. In  2016 , some cars cost  $980 more than the cost of a new Accord.How much does the other cars cost (in dollars)in 2016?

Answer:

a

     The cost of  a new Accord in 2013 compared to 2010 is  z  =  f(13) -  f(10)

b

   The magnitude at which the cost of   a new Accord in 2013 is greater          than the cost in 2010 is  

          x =  \frac{f(13)}{f(10)}

c

    The cost of the other cars is 2016 is   r  =  980 + f(16)

Step-by-step explanation:

From the question we are told that

     The cost (in dollars) of a new Honda Accord is  f(t)

       Where t is  number of years after 2000

The cost of the  Honda Accord at 2013 is  

        f(2013 - 2000) =  f(13)

The cost of the  Honda Accord at 2010 is  

        f(2010 - 2000) =  f(10)

So the cost difference between 2013 and 2010 is mathematically evaluated as

         z  =  f(13) -  f(10)

Let constant at which the cost of Honda Accord in 2013 is greater than its cost at 2010 be  x

So

      f(13) =  x f(10)

=>      x =  \frac{f(13)}{f(10)}

  The cost of the Honda Accord in 2016 is mathematically evaluated as

          f(2016 - 2000) =   f(16)    

Now the cost of these other cars is  mathematically evaluated as  

         r  =  980 + f(16)

7 0
3 years ago
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