Answer:
reflection...................
Answer: 7 days
Step-by-step explanation:
Camille and Hiroki have decided to start walking for exercise. Camille is going to walk 7 miles the first day and 3 miles each day after that. Hiroki is too busy to walk on the first 2 days, so he decides to walk 5 miles each day until he has walked the same number of miles as Camille.
Camille will walk x days, so: 7 + 3(x-1) miles
Hiroki will walk the same miles, but 2 days less so: 5(x-2)
same amount of miles:
5(x-2) = 7 + 3(x-1)
5x - 10 = 7 + 3x - 3
5x - 3x = 10 + 7 - 3
2x = 14
x = 7
If Camille and Hiroki will have walked the same number of miles, how many days will Camille have walked?
Camille will have walked 7 days.
We use the equation for repeated trials written below:
Probability = n!/r!(n-r)! * p^(n-r) * q^r
The p is the probability of getting a side A in one toss. Since a counter has only two side, p = 0.5. The q is the probability of not getting side A in one toss, which is also q = 0.5. Now, r is the number of success per n trials. There are 3 tosses so, n=3. The question is getting "at least 1" counter. So, r=1, r=2 and r=3.
Probability for r=1: 3!/1!(3-1)! * (0.5)^(3-1) * (0.5)^1= 0.375
Probability for r=2: 3!/2!(3-2)! * (0.5)^(3-2) * (0.5)^2= 0.375
Probability for r=1: 3!/3!(3-3)! * (0.5)^(3-3) * (0.5)^3= 0.125
Total probability = 0.375 + 0.375 + 0.125 = 0.875
Answer:
y = 
x - 1
Step-by-step explanation:
5x + 2y = 12
2y = -5x + 12
y = x + 6
y = mx + b
4 = ( -2 ) + b
4 = 5 + b
b = -1
y = x - 1
