P of selecting point on the shaded region = shaded area/whole area
<span>P( selecting point on the shaded ) = ( the four shaded circles ) / the whole square </span>
<span>P of selecting point on the shaded = ( 4 * ( π * r^2 ) )/ x^2 </span>
<span>P of selecting point on the shaded = ( 4 * ( π * (x/4)^2 ) )/ x^2 </span>
<span>P of selecting point on the shaded = ( 4 * ( π * x^2/16 ) )/ x^2 </span>
<span>P of selecting point on the shaded = ( π * x^2/4 )/ x^2 </span>
<span>P of selecting point on the shaded = x^2( π/4 )/ x^2 </span>
<span>P( selecting point on the shaded ) = π/4 ≈ 0.7854 ≈ 79%
=80%
D is right option hope this helps</span>
K(cannot equal (the = sign with the line through it) -2
k(=/)-2
Answer:
899.5
Step-by-step explanation:
Answer:
1/6
Step-by-step explanation:
You have one die, with one 4 and six sides. The probability of getting a 4 with one roll is 1/6.
Answer:
x = 6.
y = 6.7.
z = 13.4.
Step-by-step explanation:
The 2 triangles contained in the biggest one are similar, so:
x/12 = 3/x
x^2 = 36
x = 6.
Applying the Pythagoras theorem:
z^2 = 6^2 + 12^2
z^2 = 36 + 144 = 180
z = 13.4.
y^2 = x^2 + 3^2
= 36 + 9
= 45
y = 6.7
