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Liula [17]
3 years ago
15

16y=14+9y please answer 23 points

Mathematics
1 answer:
NeTakaya3 years ago
4 0

Answer:

<h2>y = 2</h2>

Step-by-step explanation:

16y=14+9y\qquad\text{subtract}\ 9y\ \text{from both sides}\\\\16y-9y=14+9y-9y\\\\7y=14\qquad\text{divide both sides by 7}\\\\\dfrac{7y}{7}=\dfrac{14}{7}\\\\y=2

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Answer:

2571.14

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Step-by-step explanation:

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Need asap please. Brainliest for correct answer.
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Correct answer is
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Fernando is making 30 sundaes with mint, chocolate,and vanilla ice cream.1/3 of the Sunday's are mint ice-cream and 1/2 of the r
Alina [70]

Answer:

<u>10 sundaes</u> will be vanilla.

Step-by-step explanation:

Given:

Fernando is making 30 sundaes with mint, chocolate,and vanilla ice cream.

1/3 of the Sunday's are mint ice-cream.

And 1/2 of the remaining sundaes are chocolate.

The rest are vanilla.

Now, to find the number of sundaes that will be vanilla.

Fernando is making sundaes total = 30.

So, the quantity of sundaes that are mint ice-cream:

\frac{1}{3} \ of\ 30\\\\=\frac{1}{3} \times 30\\\\=10.

<em>Thus, 10 sundaes are mint ice-cream.</em>

So, the remaining sundaes are:

30-10=20.

<em>Thus, the remaining sundaes are = 20.</em>

Now, to get the quantity of chocolate sundaes of the remaining sundaes:

\frac{1}{2} \ of\ 20\\\\=\frac{1}{2} \times 20\\\\=10.

<em>Hence, 10 sundaes are chocolate of the remaining 20 sundaes.</em>

<em>As, given the rest are vanilla.</em>

Now, to get the vanilla sundaes we subtract the 10 chocolate ice-cream from the 20 remaining sundaes:

20-10=10.

Therefore, 10 sundaes will be vanilla.

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It separate what you are looking for
3 0
3 years ago
I can’t figure out which formula goes with which sequence. Help……. Please???
Radda [10]

For a geometric sequence

<em>a</em>, <em>ar</em>, <em>ar</em> ², <em>ar</em> ³, …

the <em>n</em>-th term in the sequence is <em>ar</em> <em>ⁿ</em> ⁻ ¹.

The first sequence is

1, 3, 9, 27, …

so it's clear that <em>a</em> = 1 and <em>r</em> = 3, and so the <em>n</em>-th term is 3<em>ⁿ</em> ⁻ ¹.

The second sequence is

400, 200, 100, 50, …

so of course <em>a</em> = 400, and you can easily solve for <em>r</em> :

200 = 400<em>r</em>   ==>   <em>r</em> = 200/400 = 1/2

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Similarly, the other sequences are given by

3rd: … 4 × 2<em>ⁿ</em> ⁻ ¹

4th: … 400 (1/4)<em>ⁿ</em> ⁻ ¹

5th: … 5<em>ⁿ</em> ⁻ ¹

6th: … 1000 (1/2)<em>ⁿ</em> ⁻ ¹

7th: … 2 × 5<em>ⁿ</em> ⁻ ¹

7 0
3 years ago
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