3 years ago

. Where does the line y = 3x + 5 cross the y-axis?

1 answer:

4 0

Answer: at 5

Step-by-step explanation: the 3 is the slope and the 5 is the y intercept. The y-intercept corresponds to the value of 5 when the x value is equal to 0

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Given that cos θ = –12∕13 and θ is in quadrant III, find csc θ.

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Answer:

Step-by-step explanation:

We are given:

$\displaystyle \cos(\theta)=-\frac{12}{13},\,\theta\in\text{QIII}$

Since cosine is the ratio of the adjacent side over the hypotenuse, this means that the opposite side is (we can ignore negatives for now):

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And since θ is in QIII, sine/cosecant is negative, cosine/secant is negative, and tangent/cotangent is positive.

Cosecant is given by the hypotenuse over the opposite side. Thus:

$\displaystyle \csc(\theta)=\frac{13}{5}$

Since θ is in QIII, cosecant must be negative:

$\displaystyle \csc(\theta)=-\frac{13}{5}$

Our answer is A.

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