19 is a prime number so 1, 19
hope this helps!
The answer I got is (-6,-2) the x value is -6
Answer:
Explanation has been given below
Step-by-step explanation:
a) inter arrival times are exponentially distributed with mean 1/n , where n = rate = 1/sec.
probability distribution function is F(t)=n*exp(-n*t).
reference to any kth packet and the (k-1)th packet
the answer is = integration of F(t).dt with limits 0 to 2 = 1 - exp(-2*n) = 1 - exp(-2)
b) t=5 , P(q) = exp(-5)*(5)^q/factorial(q)
probability of fourth call within t=5 seconds is =
that is P(4) P(5) ...... = 1 - ( P(0) P(1) P(2) P(3) ) ; put the values and get the answer.
c) number of calls/rate = 4/n = 4 seconds
1. Since it's m - 7 you would have 7 to both sides so you would in fact have m < 13. If you double check your answer, you see that if m is say 12 (because 12 is obviously less than 13), 12 - 7 < 6
2. Again, use the same process on this problem as the first one. Add 8 to each sides because it's you're subtracting 8 from n. So you end up with n > 13. Check your answer. Say n is 14. 14 - 8 > 5
3. This one is different because you are adding 5 to p. So in order to get p by itself, you need to subtract 5 from both sides. p < 5. Say p is 4, 4 + 5 < 10.
When working with problems like these, you need to isolate the variable on one side and get it by itself.
