The time taken for the ball to fall a distance of 10feet is 1.25secs
Given the function modeled by the height expressed as:
f(t) =-16t² + 35
In order to determine the time taken by the all to fall a distance of 10 feet, hence;
f(t) = 10
10 = -16t² + 35
-16t² = 10 - 35
-16t² = -25
-t² = -25/16
t² = 25/16
t = √25/16
t = 5/4
t = 1.25secs
Hence the time taken for the ball to fall a distance of 10feet is 1.25secs
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Answer:
= 30,550 rupee owed
Step-by-step explanation:
yr1 = 50000 x 0.10^1 = 5000
5000 - 10000 = 5000 credit from debt.
yr 2 = 50000 x 1.10^2 = 500 debit from debt = 5000-15000= 10,000 credit from debt
yr 3 = 50000 x 1.10^3 = 50 debit from debt
5000 + 500 = 15000 where 50,000 owed initially and yr1 and yr 2 paid in full interest of 5500 and we deduct this from his payment = 25000-5500 =
19500 paid of initial and nothing owed on interest.
50000-19500= 30,500 rupees owed + 50 rupee interest.
= 30,550 rupee owed
(3n)-2=5
Move all numbers without a variable to the right side of the equation
3n=7
Divide 7 by 3
n=2.333
1 1/2 feet= 18 inches
18 inches/3 = 6
Answer:
C
Step-by-step explanation:
In this technique, if we have to factorise an expression like ax2+bx+c, we need to think of 2 numbers such that:
N1⋅N2=a⋅c=1⋅−12=−12
AND
N1+N2=b=−1
After trying out a few numbers we get N1=3 and N2=−4
3⋅−4=−12, and 3+(−4)=−1
x2−x−12=x2−4x+3x−12
x(x−4)+3(x−4)=0
(x+3)(x−4)=0
Now we equate the factors to zero.
x+3=0,x=−3
x−4=0,x=4
