All categories

3 years ago

What is equal to 3log2 + log4

Mathematics

2 answers:

Sunny_sXe [5.5K]3 years ago

7 0

Well I tried sloving it and I got 1.5

sineoko [7]3 years ago

4 0

Log Rule #1: log(x*y) = log(x)+log(y)
Log Rule #2: log(x^y) = y*log(x)

Using those log rules, we can say...

3*log(2) + log(4) = log(2^3) + log(4) <-- use log rule #2
3*log(2) + log(4) = log(8) + log(4) <-- simplify 2^3 to get 8
3*log(2) + log(4) = log(8*4) <-- use log rule #1
3*log(2) + log(4) = log(32) <-- simplify 8*4 to get 32

So the expression simplifies to log(32)

You might be interested in

Q1. In a fruit cocktail, for every 30 ml

lora16 [44]

Answer:

3/10

Step-by-step explanation:

$\frac{30}{30 + 20 + 50} = \frac{3}{10}$

5 0

2 years ago

The diagonals of a rhombus measures 6cm and 8cm, what is the perimeter of this rhombus?

Kamila [148]

<h2><u>Diagram</u><u>:</u><u>-</u></h2>

$\setlength{\unitlength}{1 cm}\begin{picture}(20,15)\thicklines\qbezier(1,1)(1,1)(6,1)\qbezier(1,1)(1,1)(1.6,4)\qbezier(1.6,4)(1.6,4)(6.6,4)\qbezier(6,1)(6,1)(6.6,4)\qbezier(6.6,4)(6.6,4)(1,1)\qbezier(1.6,4)(1.6,4)(6,1)\put(0.7,0.5){\sf A}\put(6,0.5){\sf B}\put(1.4,4.3){\sf D}\put(6.6,4.3){\sf C}\end{picture}$

<h3><u>Required Answer</u><u>:</u><u>-</u></h3>

The diagonals of the Rhombus= d1 & d2=6cm and 8cm

Let the Side=a

As we know that in a Rhombus

${\boxed{\sf side=\sqrt {\left ({\dfrac{d1}{2}}\right)^2+\left ({\dfrac {d2}{2}}\right)^2}}}$

Substitute the values

${:}\longmapsto$ $\sf a=\sqrt {\left ({\dfrac {6}{2}}\right)^2+\left ({\dfrac {8}{2}}\right)^2 }$

${:}\longmapsto$ $\sf a=\sqrt {(3)^2+(4)^2}$

${:}\longmapsto$ $\sf a=\sqrt {9+16}$

${:}\longmapsto$ $\sf a=\sqrt{25}$

${:}\longmapsto$ $\sf a=5cm$

<h2>_____________</h2><h3>Again </h3>

we know that in a Rhombus

$\boxed{\sf Perimeter=4a}$

Substitute the values

${:}\longmapsto$ $\sf Perimeter=4×5$

${:}\longmapsto$ $\sf Perimeter=20cm$

$\therefore$ Perimeter of the rectangle is 20cm.

5 0

3 years ago

The frequency distribution shows the lengths, in inches, of available baseball bat at a batting cage. what is the mean of the fr

ivanzaharov [21]

The mean of a frequency distribution is given by
<span>
$\bar{x}= \frac{\Sigma fx}{\Sigma f} \\ \\ = \frac{(27\times2)+(28\times5)+(31\times3)+(33\times1)+(34\times4)}{2+5+3+1+4} \\ \\ = \frac{54+140+93+33+136}{15} = \frac{456}{15} =30.4$ </span>