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3 years ago

What is equal to 3log2 + log4

Mathematics

2 answers:

Sunny_sXe [5.5K]3 years ago

7 0

Well I tried sloving it and I got 1.5

sineoko [7]3 years ago

4 0

Log Rule #1: log(x*y) = log(x)+log(y)
Log Rule #2: log(x^y) = y*log(x)

Using those log rules, we can say...

3*log(2) + log(4) = log(2^3) + log(4) <-- use log rule #2
3*log(2) + log(4) = log(8) + log(4) <-- simplify 2^3 to get 8
3*log(2) + log(4) = log(8*4) <-- use log rule #1
3*log(2) + log(4) = log(32) <-- simplify 8*4 to get 32

So the expression simplifies to log(32)

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Rearrange the formula to make x the subject.<br><br> y = 4x + 3

allochka39001 [22]

Answer:

$x=\frac{y-3}{4}$

Step-by-step explanation:

$y=4x+3$

$y-3=4x$

$\frac{y-3}{4}=x$

$x=\frac{y-3}{4}$

4 0

3 years ago

Read 2 more answers

Which measure of central tendency best represents the most requested song at a radio station?

tamaranim1 [39]

The mode because it is the number that occurs more often but in this situation it would be most requested song.

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3 years ago

Shows that n+1Cn= mCn-1 + mCn

ArbitrLikvidat [17]

Answer:

I think the Question is incorrect; the left hand side of the equation should be

m+1Cn

Step-by-step explanation:

4 0

3 years ago

A slug travels 3 centimeters in 3 seconds. A snail travels 6 centimeters in 6 seconds Both travel at constant speeds. Mai says,

Mashutka [201]

Answer:

No I dont agree with Mai. As both the slug and snail are moving with constant speed.

Step-by-step explanation:

Given that:

A slug travels 3 centimeters in 3 seconds.

Speed of slug = distance/ time = 3/3 = 1 cms^-1

A slug travels 3 centimeters in 3 seconds.

Speed of snail = distance/ time = 6/6 = 1 cms^-1

Hence both have constant speeds only the time span for snail is increased which gives more distance it doesn't means that it had covered more distance.

i hope it will help you!

4 0

3 years ago

I GIVE BRAINLIEST PLS HELP

ioda

The answer is 8
Here's why:
${ ( \frac{( {6}^{7}) \times ( {3}^{3}) }{( {6}^{6}) \times ( {3}^{4} ) } )}^{3} = \\ ( \frac{6}{3} ) ^{3} = \\ \frac{216}{27} = 8$
The exponents are subtracted one from another when divided.
$\frac{ a ^{b} }{ {a}^{c} } = {a}^{b - c}$
We can look at the problem this way:
$( \frac{6^{7} }{6 ^{6} } \times \frac{3^{3} }{ {3}^{4} } ) = (6^{7 - 6} \times {3}^{3 - 4} ) = \\ ({6}^{1} \times {3}^{ - 1} )$
Since we have the power of -1 on the 3, we apply this rule:
${a}^{ - b} = \frac{1}{ {a}^{b} }$
Also this rule because we have the power of 1 on the 6:
${a}^{1} = a$
Then we get this:
$(6 \times \frac{1}{3} )^{3} = ( \frac{6}{3} )^{3}$
We apply the rule:
$( \frac{a}{b}) ^{c} = \frac{ {a}^{c} }{ {b}^{c} }$
We get this:
$\frac{{6}^{3} }{ {3}^{3} } = \frac{216}{27} = 8$

4 0

3 years ago