Answer:
I can
Step-by-step explanation:
I'm taking precalculus currently
Johnny is selling tickets to a school play. On the first day of ticket sales he sold 14 senior (S) citizen tickets and 4 child (C) tickets for a total of $200. On the second day of ticket sales he sold 7 senior (S) citizen tickets and 1 child (C) ticket for a total of $92. What is the price of one child ticket?
14S + 4C = 200
14S = 200 - 4C
S = (200 - 4C)/14
7S + 1C = 92
7S = 92 - C
S = (92 - C)/7
(200 - 4C)/14 = (92 - C)/7
7 x (200 - 4C) = 14 x (92 - C)
1400 - 28C = 1288 - 14C
1400 - 1288 = 28C - 14C
112 = 14C
C = 112/14 = 8
the price of one child ticket = $8
What is the circumference of the circle?
answer: D) 69.08
explanation:
You are going in the right direction. For the distance of ST I get √136
√(-5-1)² + (6+4)² =
√(-6)² + (10²) =
√ 36 + 100 =
√136
√34² + √136² =√170²
34 + 136 = 170
170 = 170
Brian as 8 cards.
The fraction that show how many are baseball cards is 5/8, because 5 cards from the total amount are baseball cards. Good luck !