<em>Answer:</em>
<em>x ≅ 79.1</em>
<em>Step-by-step explanation:</em>
<em>10log(4x) = 25 </em>
<em>2log(4x) = 5 </em>
<em>log((4x)²) = 5 </em>
<em>(4x)² = 10⁵ </em>
<em>16x² = 100,000 </em>
<em>x² = 6,250 </em>
<em>x ≅ 79.1</em>
In order for a function...to be called a function , is that for every x, there must always only be one y. Two x's can have the same y, but the same x can't have two separate y's. One way to test this is the vertical line test. You basically put up a vertical line on the graph. The artificial line (you can do it with your finger, pencil, etc.) should only intersect once on the graph. So, take your pencil, and hold it up to down (like this | ) on your monitor. You see that when you do that, it intersects with the graph twice. That means it DOESN'T pass the vertical line test, which means it is not a function (Function are not always straight lines, which is why the first two are wrong). So, the answer is
D)
I find that if you transform fractions into decimals, they become marginally easier to work with. Nine over five in decimal form is one point eight. If we divide 1.8 by three (Jean-Claude and his two friends), then we come up with the answer 0.6, which, once turned back into a fraction, would be six over ten, or three over five.
A and B are correct for this one!!
Y = -2x^2
h = Xv = -B/2A = 0/-4 = 0.
k = -2*0^2 = 0.
V(0,0).
Use the following points for graphing:
Y = -2x^2.
(x,y)
(-2,-8)
(-1,-2)
V(0,0)
(1,-2)
(2,-8)
Y = -2x^2 + 4.
h = Xv = -B/2A = 0/-4 = 0.
k = Yv = -2*0^2 + 4 = 4.
V(0,4).
(-2,-4)
(-1,2)
V(0,4)
(1,2)
(2,-4)
