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Zigmanuir [339]
2 years ago
15

the function f(x)=1/6{2/5}x is reflected across the y axis to create the function g(x). which ordered pair is on g(x)

Mathematics
2 answers:
Sergeeva-Olga [200]2 years ago
8 0
When  you reflect a function across the y-axis the new function is obtained by changing x for (-x)


So, when  you reflect y = (1/6) [2.5]^(x) across the y-axis you create the function g(x) = (1/6) [2.5] ^(-x)


Now, to obtain the ordered pairs, you just give a value to x and calculate g(x).


This table shows some ordered pairs:


x                  g(x) = (1/6) * (2.5) ^ (-x)


-10           (1/6) (2.5)^ (10) = 1,589.457

-1             (1/6) (2.5)^(1) =  0.416667

0              (1/6) (2.5)^(0) = 1/6 = 0.166667

1              (1/6) (2.5)^(-1) = 0.066667

10            (1/6)(2.5)^(-10) = 0.000017476


So, you see that to find each pair you give a value to x and then find the image replacing x in the function g(x) = (1/6)*[2.5](^-x).
vladimir1956 [14]2 years ago
6 0

Answer:

THERES NO FEAR.... THE ANSWER IS HERE!!!!

Step-by-step explanation:

ITS A :) <3

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Step-by-step explanation:

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8 0
3 years ago
If x=2/3 and x=-3 are the roots of the equation ax^2+7x+b=0 find the values of a and b
Gnesinka [82]

<u>ANSWER:  </u>

If x = \frac{2}{3} and x = -3 are the roots of the equation, then values of a and b are 3, -6

<u>SOLUTION: </u>

Given, quadratic equation is a x^{2}+7 x+b=0 and its roots are -3 , \frac{2}{3}

We know that, for any quadratic equation of form a x^{2}+b x+c=0 with roots x_{1} and x_{2} then,

Sum of roots (x_{1} +x_{2}) = \frac{-b}{a}

Product of roots ( x_{1} \times x_{2}) = \frac{c}{a}

Now, for given quadratic equation x_{1} = -3 and x_{2} = \frac{2}{3}

hence Sum of roots = \frac{-7}{a}

x_{1} + x_{2} = \frac{-7}{a}

-3 + \frac{2}{3} = \frac{-7}{a}

on solving we get "a" = 3

Now product of roots = x_{1} \times x_{2} = \frac{b}{3}

-3 \times \frac{2}{3} = \frac{b}{3}

b = -6

hence, the values of a and b are 3, -6.

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3 years ago
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Answer:

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Step-by-step explanation:

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2 years ago
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