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densk [106]
3 years ago
14

Yet another reaction has an equilibrium constant kc=4.32×105 at 25 ∘c. it is an exothermic reaction, giving off quite a bit of h

eat while the reaction proceeds. if the temperature is raised to 200 ∘c , what will happen to the equilibrium constant? the equilibrium constant will yet another reaction has an equilibrium constant at 25 . it is an exothermic reaction, giving off quite a bit of heat while the reaction proceeds. if the temperature is raised to 200 , what will happen to the equilibrium constant?
Chemistry
2 answers:
Tatiana [17]3 years ago
8 0
The equilibrium constant will decrease.
when this reaction is an exothermic reaction, SO we can assume heat as a product of that reaction.

when Kc = concentration of product/concentration of reactants

So when the temperature and heat increase the reaction will go in the direction which decreases the heat and achieves equilibrium again. So it will go leftwards to decrease the products. and when the products decrease the Kc will decrease. 

Kitty [74]3 years ago
4 0
<span><u><em>Answer:</em></u>
The equilibrium constant will decrease

<u><em>Explanation:</em></u>
<u>The equilibriuc constant (Kc) can be calculated as follows:</u>
Kc = </span>\frac{concentration_o_fproducts}{concentration_o_freactants}<span>

Now, the given equation is an exothermic reaction. This means that <u>heat is s product.</u>

If we increase the amount of heat, the system will no longer be at equilibrium. This equilibrium will <u>shift to the left creating more reactants</u> in order to balance the system and be reach equilibrium again.

By this, we can note that the <u>concentration of reactants in the system will increase</u> which means that the equilibrium constant will decrease.

Hope this helps :)</span>
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francium

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A solution is made by mixing 37.g of thiophene C4H4S and 72.g of heptane C7H16. Calculate the mole fraction of thiophene in this
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Answer:

0.38

Explanation:

Molar mass of thiophene= 84g/mol

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Molar mass of heptane= 100 g/mol

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Number of moles = 72/100= 0.72 moles

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3 years ago
Reacting 35.4 ml of 0.220 m agno3 with 52.0 ml of 0.420 m k2cro4 results in what mass of solid formed
laila [671]
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