Explanation:Reaction Type
Double Displacement (Metathesis)
Net Ionic Equation
Ba(C2O4) + 2K(IO3) = Ba(IO3)2 + K2(C2O4) might be an ionic equation. Calculate the net ionic equation for Ba(C2O4)(s) + 2K(IO3)(aq) = Ba(IO3)2(aq) + K2(C2O4)(aq).
Answer:
3.4g
Explanation:
Given parameters:
Mass of ethanol = 2.911g
Unknown:
Mass of water vapor = ?
Solution:
To solve this problem, let us write the balanced reaction equation first;
C₂H₅OH + 3O₂ → 2CO₂ + 3H₂O
Now find the number of moles of ethanol;
Number of moles =
Molar mass of ethanol = 2(12) + 5(1) + 16 + 1 = 46g/mol
Number of moles = = 0.06mole
So;
1 mole of ethanol will produce 3 moles of water vapor
0.06mole of ethanol will produce 0.06 x 3 = 0.19moles of water vapor
Mass of water vapor = number of moles x molar mass
Molar mass of H₂O = 2(1) + 16 = 18g/mol
Mass of water vapor = 0.19 x 18 = 3.4g
Considering the reaction:
3NO₂ + H₂O → 2HNO₃ + NO
To produce 3.56 moles of nitric acid, we require:
3.56 x 3/2 moles of NO₂
Moles of NO₂ = 5.34 moles of NO₂
Answer:
No the material obtained by the two groups don't look the same.
Explanation:
For a hydrocarbon, the combustion reactions are the following:
C + O₂ --> CO₂
H₂ + 1/2 O₂ --> H₂O
The molar mass of CO₂ is 44 g/mol while C is 12 g/mol. Let's solve for amount of C in hydrocarbon.
Mass of C = (14.1 g CO₂)(1mol/44g)(1 mol C/1 mol CO₂)(12 g/mol) = 3.845 g C
So, that means that the mass of hydrogen is:
Mass of H = 4.4 - 3.845 = 0.555 g
Moles C = 3.845/12 = 0.32042
Moles H = 0.555/1 = 0.555
Divide both by the smaller value, 0.32042.
C: 0.32042/0.32042 = 1
H: 0.555/0.32042 = 1.732
We have to get an answer that is closest to a whole number. Let's try multiplying both with 4.
C: 1*4 = 4
H: 1.732*4 = 6.93≈7
<em>Thus, the empirical formula is C₄H₇.</em>