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2 years ago

HELP ME!!! THIS IS DUE IN 6 MINUTES!

Mathematics

1 answer:

ipn [44]2 years ago

3 0

Step-by-step explanation:

Descending order means that the exponents are going from greatest to smallest.

$5x^2-3x^3+7+2x$

Now, let's rearrange the terms so they are going in descending order.

$-3x^3+5x^2+2x+7$

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Let 3x^2+kx+4. determine all values of k such that the quadratic equation f(x) =0 has one real root

user100 [1]

//I'll use the discriminant rule for this.
b^2 - 4ac = 0 when one real root

Therefore, k^2 - 4*3*4= 0
k^2 = 48
k= +-4√3

7 0

3 years ago

mihalych1998 [28]

Answer

Secured

Step-by-step explanation:

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3 years ago

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HELP ME?!?!?

OLEGan [10]

Answer:

its 3 inches

Step-by-step explanation:

Because 9 divided by 3 is 3 (in.) as well as 6 divided by 2 and if its equilateral, all sides are the same (i hope this makes sense)

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3 years ago

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Let ρ = x3 + xe−x for x ∈ (0, 1), compute the center of mass.

hram777 [196]

The center of mass is mathematically given as

$\bar{x}=\left(\frac{44 e-100}{25 e-40}\right)\end{aligned}$

<h3>What is the center of mass.?</h3>

Determine the center of mass in one dimension:

Represent the masses at the respective distances.

$\begin{|c|c|} Masses \ & \ \ \ \ \ \ \ \ \ \ \ \ \ \ Located at \\\rho=x^{3}+x \cdot e^{-x} & \ \ \ \ x \in(0,1)$ \\\end$

We calculate the total mass of the system.

$\begin{aligned}m &=\int_{0}^{1} \rho \cdot d x \\& m =\int_{0}^{1}\left(x^{3}+x \cdot e^{-x}\right) \cdot d x \\&m =\left|\frac{x^{4}}{4}-(x+1) e^{-x}\right|_{0}^{1} \\&m =\left(\frac{5}{4}-\frac{2}{e}\right)\end{aligned}$

Step 03: Calculate the moment of the system.

$\begin{aligned}M &=\int_{0}^{1}(\rho \cdot x) \cdot d x \\& M=\int_{0}^{1}\left(x^{4}+x^{2} \cdot e^{-x}\right) \cdot d x \\&M =\left|\frac{x^{5}}{5}-\left(x^{2}-2 x+2\right) \cdot e^{-x}\right|_{0}^{1} \\&M=\left(\frac{11}{5}-\frac{5}{e}\right)\end{aligned}$

we calculate the center of mass.

$\begin{aligned}\bar{x} &=\left(\frac{M}{m}\right) \\& \bar{x}=\left\{\left(\frac{\left.11-\frac{5}{5}\right)}{\left(\frac{5}{4}-\frac{2}{e}\right)}\right\}\right.\\& \bar{x}=\left(\frac{11 e-25}{5 e}\right) \cdot\left(\frac{4 e}{5 e-8}\right) \\&\bar{x}=\left(\frac{44 e-100}{25 e-40}\right)\end{aligned}$