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hram777 [196]
4 years ago
12

Evaluting Algebraic Expressions

Mathematics
1 answer:
Rzqust [24]4 years ago
6 0
1. 3n + 4
3(6) + 4
18 + 4
22

2. N/2 - 1
6/2 - 1
3 - 1
2

3. 15 - n
15 - 6
9

4. n² - 5
6² - 5
36 - 5
31

5. 9(N-2)
9(6-2)
9(4)
36

6. 4n / 3+1
4(6) / 4
24 / 4
6

7. 2(18-n)
2(18 - 6)
2(12)
24

Hope this helped!! If you liked my answer, please mark me as brainliest. Thank you! :9
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Answer:

Option A. -6.5

Step-by-step explanation:

we have

6.4r-5.9r=-3.25

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That means ---> isolate the variable r

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0.5r=-3.25

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Write a quadratic relation in the form y = ax2 + bx + c with roots 4 and - 3 and
pochemuha

Answer:

y =  2*x^2 - 2*x - 24

Step-by-step explanation:

If we have a quadratic function with roots a and b, we can write the equation for that function as:

y = f(x) = A*(x - a)*(x - b)

Where A is the leading coefficient.

In this case, we know that the roots are: 4 and -3

Then the function will be something like:

f(x) = A*(x - 4)*(x - (-3) )

f(x) = A*(x - 4)*(x + 3)

Now we need to determine the value of A.

We also know that the graph of the function passes through the point (3, -12)

This means that:

f(3) = -12

Then:

-12 = A*(3 - 4)*(3 + 3)

-12 = A*(-1)*(6)

-12 = A*(-6)

-12/-6 = A

2 = A

Then the equation is:

y = f(x) = 2*(x - 4)*(x + 3)

Now we need to write this in standard form, so we just need to expand the equation:

y = f(x) = 2*(x^2 + x*3 - x*4 - 4*3)

y = f(x) = 2*(x^2 - x - 12)

y = f(x) = 2*x^2 - 2*x - 24

Then the relation is:

y =  2*x^2 - 2*x - 24

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