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Mazyrski [523]
4 years ago
8

What reaction type is depicted by the following equation? 2C2H2 + 5O2 4CO2 + 2H2O decomposition combination combustion single-re

placement double-replacement
Chemistry
2 answers:
avanturin [10]4 years ago
7 0

<u>Answer:</u> The given reaction represents a combustion reaction.

<u>Explanation:</u>

Decomposition reaction is defined as the chemical reaction in which a single substance breaks down into two or more simpler substances.

AB\rightarrow A+B

Combination reaction is defined as the reaction in which two or more smaller substances combine to form a single large substance.

A+B\rightarrow AB

Combustion reaction is defined as the reaction in which a hydrocarbon reacts with oxygen gas to produce carbon dioxide and water.

C_xH_y+O_2\rightarrow CO_2+H_2O

A double displacement reaction is defined as the reaction in which exchange of ions takes place.

AB+CD\rightarrow AD+CB

A single displacement reaction is defined as the reaction in which a more reactive element displaces a less reactive element from its chemical reaction.  The reactivity of metal is determined by a series known as reactivity series.

AB+C\rightarrow CB+A

Metal C is more reactive than metal A.

For the given chemical reaction:

2C_2H_2+5O_2\rightarrow 4CO_2+2H_2O

This is considered as a combustion reaction because ethene reacts with oxygen gas to produce carbon dioxide and water molecule.

Vladimir [108]4 years ago
3 0

combustion is when you burn something in presence e of oxygen and the products will be mainly the CO2 and H2O

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An inverted pyramid is being filled with water at a constant rate of 45 cubic centimeters per second. The pyramid, at the top, h
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13.20 cm/s is the rate at which the water level is rising when the water level is 4 cm.

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Volume of the pyramid = V=\frac{1}{3}lwh

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Volume of the square based pyramid = V

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Differentiating V with respect to dt:

\frac{dV}{dt}=\frac{d(\frac{12}{169}h^3)}{dt}

\frac{dV}{dt}=3\times \frac{12}{169}h^2\times \frac{dh}{dt}

45 cm^3/s=3\times \frac{12}{169}h^2\times \frac{dh}{dt}

\frac{dh}{dt}=\frac{45 cm^3/s\times 169}{3\times 12\times h^2}

Putting, h = 4 cm

\frac{dh}{dt}=\frac{45 cm^3/s\times 169}{3\times 12\times (4 cm)^2}

=13.20 cm/s

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