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kiruha [24]
2 years ago
15

A sample of the element lead has a mass of 63.466 g. In units of milliliters what will be the volume of the sample at 25°C?

Chemistry
2 answers:
pickupchik [31]2 years ago
8 0
Tbh I don’t kno this but I will look far word to tryna see wassuh tho
borishaifa [10]2 years ago
5 0

Answer:

9+10=21

Explanation:

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Name any <br>three kinds of mixtures with example​
sleet_krkn [62]

Answer:

Here are a few more examples:

Smoke and fog (Smog)

Dirt and water (Mud)

Sand, water and gravel (Cement)

Water and salt (Sea water)

Potassium nitrate, sulfur, and carbon (Gunpowder)

Oxygen and water (Sea foam)

Petroleum, hydrocarbons, and fuel additives (Gasoline)

Heterogeneous mixtures possess different properties and compositions in various parts i.e. the properties are not uniform throughout the mixture.

Examples of Heterogeneous mixtures – air, oil, and water, etc.

Examples of Homogeneous mixtures – alloys, salt, and water, alcohol in water, etc.

Explanation:

8 0
2 years ago
Read 2 more answers
As the volume of a gas increases, what happens to the pressure of the gas?
Elena L [17]
Boyle found that when the pressure of gas at a constant temperature is increased, the volume of the gas decreases. when the pressure of gas is decreased, the volume increases. this relationship between pressure and volume is called Boyle's law.
4 0
2 years ago
Consider the following intermediate reactions.
Alja [10]

2.1648 kg of CH4 will generate 119341 KJ of energy.

Explanation:

Write down the values given in the question

CH4(g) +2 O2 → CO2(g) +2 H20 (g)

ΔH1 = - 802 kJ

2 H2O(g)→2 H2O(I)

ΔH2= -88 kJ

The overall chemical reaction is

CH4 (g)+2 O2(g)→CO2(g)+2 H2O (I) ΔH2= -890 kJ

CH4 +2 O2 → CO2 +2 H20

(1mol)+(2mol)→(1mol+2mol)

Methane (CH4) = 16 gm/mol

oxygen (O2) =32 gm/mol

Here 1 mol CH4 ang 2mol of O2 gives 1mol of CO2 and 2 mol of 2 H2O

which generate 882 KJ /mol

Therefore to produce 119341 KJ of energy

119341/882 = 135.3 mol

to produce 119341 KJ of energy, 135.3 mol of CH4 and 270.6 mol of O2 will require

=135.3 *16

=2164.8 gm

=2.1648 kg of CH4

2.1648 kg of CH4 will generate 119341 KJ of energy

4 0
3 years ago
Read 2 more answers
In 1909 Fritz Haber discovered the workable conditions under which nitrogen, N2(g), and hydrogen, H2(g), would combine using to
labwork [276]

Answer : 51.8 g of nitrogen are needed to produce 100 grams of ammonia gas.

Solution : Given,

Mass of NH_3 = 100 g

Molar mass of NH_3 = 27 g/mole

Molar mass of N_2 = 28 g/mole

First we have to calculate moles of NH_3.

\text{ Moles of }NH_3=\frac{\text{ Mass of }NH_3}{\text{ Molar mass of }NH_3}= \frac{100g}{27g/mole}=3.7moles

The given balanced chemical reaction is,

N_2(g)+3H_2(g)\rightarrow 2NH_3(g)

From the given reaction, we conclude that

2 moles of NH_3 produced from 1 mole of N_2

3.7 moles of NH_3 produced from \frac{1mole}{2mole}\times 3.7mole=1.85moles of N_2

Now we have to calculate the mass of N_2.

Mass of N_2 = Moles of N_2 × Molar mass of N_2

Mass of N_2 = 1.85 mole × 28 g/mole = 51.8 g

Therefore, 51.8 g of nitrogen are needed to produce 100 grams of ammonia gas.

5 0
2 years ago
At what temperature would a 1.50 m nacl solution freeze, given that the van't hoff factor for nacl is 1.9? kf for water is 1.86
IRINA_888 [86]
Win to ki ne lei ma ki mna mata ki ss kk
5 0
2 years ago
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