Answer:
Hydroxylamine and pyridine
Explanation:
Just did it
Element name = <u>strontium</u>
d G = 2 (dG NOCl) - 2 (dG NO)
= 2 * 66.08 - 2 * 87.6 = -43.04 kJ /mol
dG = - 2.303 RT log K
-43.04 = - 2.303 RT log K
7.54 = log K
K = 3.42 * 10^7
Kp = k (RT)^dn
d n = 2 - 1 -2 = -1
Kp = (3.42 * 10^7) (8.314 * 298)^-1
Kp = 1.31 * 10^4
Explanation:
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Answer:
D
Explanation:
The sample must contain impurity that is lower in atomic mass to sodium and since potassium has higher atomic mass to sodium, the answer is the sample contains NaCl and LiCl. We are sure already that the sample is not pure which rules out option a and option b contains sodium iodide which cannot contribute to the increase in chlorine