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Alex17521 [72]
3 years ago
13

A(n) ________ Exposure is a short term or brief exposure that may create an immediate health hazard. A. Acute B. Chronic C. Emer

gency D. Short
Chemistry
2 answers:
Yanka [14]3 years ago
7 0
A(n) Acute exposure is a short term or brief exposure that may create an immediate health hazard. Answer: A)
Elina [12.6K]3 years ago
4 0

Answer: A. Acute

Explanation:

An acute exposure can be define as the exposure of the substance, a living agent or organism to a radiation, substance, particle or poison for a short period of time. These radiation, particle, substance or poison are capable of causing harm to the exposed agent causing health hazards which show immediate symptoms.  

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HELP QUICK!! Match the term with the definition. (4 points)
Rufina [12.5K]

Answer:

1. c.

2. d.

3. b.

4. a.

Explanation:

7 0
3 years ago
Read 2 more answers
Which two functional groups react to form an easter linkage?
7nadin3 [17]

Answer: You know that monomers that are joined by condensation polymerization have two functional groups. You also know (from Part 6) that a carboxylic acid and an amine can form an amide linkage, jand a carboxylic acid and an alcohol can form an ester linkage.

5 0
3 years ago
The superheated water vapor is at 15 MPa and 350°C. The gas constant, the critical pressure, and the critical temperature of wat
Vesnalui [34]

Answer:

0.01917 m^3/kg.

Explanation:

Given:

P = 15 MPa

= 1.5 × 10^4 kPa

T = 350 °C

= 350 + 273

= 623 K

Molar mass of water, m = (2 × 1) + 16

= 18 g/mol

= 0.018 kg/mol

R = 0.4615 kPa·m3/kg·K

Using ideal gas equation,

P × V = n × R × T

But n = mass/molar mass

V = (R × T)/P

V/M = (R × T)/P × m

= (0.4615 × 623)/1.5 × 10^4

= 0.01917 m^3/kg.

4 0
3 years ago
A mixture of 454 kg of applesauce at 10 degrees Celsius is heated in a heat exchanger by adding 121300 kJ. Calculate the outlet
stira [4]

Explanation:

The given data is as follows.

           Mass of apple sauce mixture = 454 kg

           Heat added (Q) = 121300 kJ

 Heat capacity (C_{p}) of apple sauce at 32.8^{o}C = 4.0177 kJ/kg^{o}C

So, Heat given by heat exchanger = heat taken by apple sauce

                            Q = mC_{p} \Delta T

or,                    Q = mC_{p} (T_{f} - T_{i})  

Putting the given values into the above formula as follows.

                     Q = mC_{p} (T_{f} - T_{i})  

              121300 kJ = 454 kg \times 4.0177 kJ/kg^{o}C \times (T_{f} - 10)

                      T_{f} = 76.5^{o}C

Thus, we can conclude that outlet temperature of the apple sauce is 76.5^{o}C.

3 0
3 years ago
In a titration, 4.7 g of an acid (HX) requires 32.6 mL of 0.54 M NaOH(aq) for complete reaction. What is the molar mass of the a
katrin2010 [14]

Answer : The molar mass of an acid is 266.985 g/mole

Explanation : Given,

Mass of an acid (HX) = 4.7 g

Volume of NaOH = 32.6 ml = 0.0326 L

Molarity of NaOH = 0.54 M = 0.54 mole/L

First we have to calculate the moles of NaOH.

\text{Moles of }NaOH=\text{Molarity of }NaOH\times \text{Volume of solution}=0.54mole/L\times 0.0326L=0.017604mole

Now we have to calculate the moles of an acid.

In the titration, the moles of an acid will be equal to the moles of NaOH.

Moles of an acid = Moles of NaOH = 0.017604 mole

Now we have to calculate the molar mass of and acid.

\text{Moles of an acid}=\frac{\text{Mass of an acid}}{\text{Molar mass of an acid}}

Now put all the given values in this formula, we get:

0.017604mole=\frac{4.7g}{\text{Molar mass of an acid}}

\text{Molar mass of an acid}=266.985g/mole

Therefore, the molar mass of an acid is 266.985 g/mole

3 0
3 years ago
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